yes it can have coz fc= c/2[(m/a)2+(n/b)2]1/2
therefore for various modes(which decide m,n) nd dimensions(a,b) of waveguide it will have different cut off frequency.
A normal waveguide is used in the octave frequency range where only the fundamental mode can propagate.
Because it has the lowest cut-off frequency (highest cut off wavelength) for a>b o
it is the frequency at which the current amplification drops 3dB below its low frequency value.
A High Pass Filter is an Electronic Filter that passes high frequency signals but Attenuates (reduces the Amplitude ) of Signals with frequencies lower than the cut-off Frequency
The beta cut off frequency is the frequency at which the current amplification of an amplifier transistor drops to three decibels below its value at 1 kilohertz. This is used in electronic engineering.
The relation between cut off frequency (fc) and band width is as follows: fc=Q*B.W where Q=(fL*fH)^1/2/(fH-fL) Q is quality factor. fL is low frequency. fH is high frequency.
If the signal frequency exceeds the cut-off frequency in a waveguide, the wave will not propagate through the waveguide and will be attenuated. This is because the waveguide is designed to support only certain modes of propagation, and frequencies above the cut-off do not satisfy the waveguide's mode conditions. Instead, the signal will either reflect back or be absorbed, leading to a loss of signal strength.
Because it has the lowest cut-off frequency (highest cut off wavelength) for a>b o
it is the frequency at which the current amplification drops 3dB below its low frequency value.
Radio waves themselves do not cut out electronics, but they can interfere with electronic devices if the frequency of the radio wave overlaps with the device's operational frequency. This interference can cause malfunctions or disruptions in communication, but it won't physically cut off power. In some cases, strong radio signals can induce currents in nearby circuits, potentially affecting their operation. However, this is more about interference than cutting out electrics.
Yes, they are both filters. But their frequency characteristics are different. This is the main reason why they are given different names. A high-pass filter passes frequencies higher than its cut-off frequency, and stops those that are lower. A low-pass filter passes frequencies lower than its cut-off frequency, and stops those that are higher.
D. H. Sinnott has written: 'The computation of waveguide fields and cut-off frequencies using finite difference techniques'
they are used in industries so to able you to work on particular frequency and cut the other for e.g if you are working for high frequency then low frequency will be cut and vise versa
A High Pass Filter is an Electronic Filter that passes high frequency signals but Attenuates (reduces the Amplitude ) of Signals with frequencies lower than the cut-off Frequency
The energy of the light is directly proportional to its frequency according to the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Therefore, if the frequency of light is cut in half, the energy of the light will also be halved.
Yes.
An artery because blood is pumped through the arteries at a much higher pressure than the veins. Therefore if you cut an artery you will lose a lot more blood a lot quicker than if you cut a vein.
Getting your hair cut implies that it is more than one strand of hair has been cut. Therefore, hairs cut is not used.