Kirchoff's Current Law: The signed sum of the currents entering a node is equal to zero.
This means that the current leaving the battery is equal to the sum of the currents in the branches of the circuit.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
3 ampere
Adding a seound battery to a series circuit will increase the voltage, and require less current to keep the lights (if there are any on) as bright. Say you have a 6v battery, then you add another 6v battery. the voltage of the circuit would be 12v
If at battery,parallel circuit shorts then equivalent resistance of circuit becomes approximately 0 Ohms,and therefore as current follows low resistance path infinite amount of current due to low resistance will flow through the wire so,entire parallel circuit will short out,but wire will burn and battery may get damaged. Name:Sumit Karnik.
Excessive current can be in the connection of many devices into a single socket.this may cause overload in the circuit
It would depend on the circuit diagram. In some cases, the circuit would be incomplete (simplest case is a battery with a wire attached to just one terminal).Parallel branches that have a connection to the battery without going through other branches are independent of each other. Say you have two parallel branches and a battery. If you short circuit one of the branches, the other branch will not be affected but the battery will be (current through the battery would decrease because taking out a parallel branch increases resistance).In short, it would depend on the circuit diagram. Note that for a nanosecond, there would be current in an open circuit, but after this brief time there would be no current flow in the segment of the circuit that has been shorted.
Kirchoff's Current Law: The signed sum of the currents entering a node is zero. Assume the top of the battery is a node. The current entering it (from the battery) is equal to the sum of the currents leaving it (to the branches). This adds up to zero.
Parallel circuit
The battery is the power source of the circuit. It supplies current to the circuit and the circuit is simply a path for the current to follow. When you remove the current (battery), the path still exists but there is no current going through it.
Hi, there. A battery is a power supply, a source of potential difference which drives current. In itself, a battery is not a circuit, but if you attach it to a load (a resistance), then a current will form and a circuit is made!
in a parallel circuit, current get divided among the parallel branches in a manner so that the product of current and the resistance of each branch becomes same. The sum of the current in each branch is equal to the total current of the circuit.
In a parallel circuit, current is divided between each of the 'branches', according to their resistance.
This type of circuit is known as a parallel circuit.
A battery contains a charge of electrons. When these electrons leave the battery and travel through a circuit that is described as current.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
The voltage measured across every component in the circuit would take on the opposite polarity from what it was originally. If there are any diodes in the circuit, then current might stop flowing in some branches where it formerly existed, or start flowing in branches where there was no current before.
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.