The secondary winding's current rating is the rated apparent power of the transformer (expressed in volt amperes) divided by its voltage rating (expressed in volts). This applies to both step down, and step up, Transformers.
Tis question is incompleet.1000 va =1 kva.This is the power capacity of transformer. A transformer having 2 currents Primary current and secondary current . for that we required both voltage. Simply we can calculate by a formula Voltage x Current x 0.8(power factor)=1000.
The "current choking" means that the maximum capacity of a transformer is not being utilized. To prevent it from ever reaching its maximum capacity a lower value of over current protection or fuse is installed. The purpose is to use larger capacity transformer available but using smaller distribution and cables just sufficient for the application to lower the installation cost.
A transformer has a rating that is usually expressed in KVA. This is approximately a wattage rating. It is not dangerous but it can be the cause of some concern. An appliance has a set current that is draws. This current times the voltage is the appliance's wattage. The same goes for the transformer. It only has a certain capacity to supply a specific current that is governed by its KVA (watts). Driving the transformer beyond its rated capacity tends to heat the transformer beyond its working temperature. If left in this over current draw the transformer's windings insulation will break down and the windings will short circuit. This is usually the end of a working transformer. So short answer, more watts (amps) from appliance equals burned out transformer.
Cable size is determined by current. You did not provide the current, nor did you include the voltage so that we could calculate the current. Please restate the question, and include either the current or the voltage.
Depends on the transformer. This can range from a few gallons to thousands of gallons.
Tis question is incompleet.1000 va =1 kva.This is the power capacity of transformer. A transformer having 2 currents Primary current and secondary current . for that we required both voltage. Simply we can calculate by a formula Voltage x Current x 0.8(power factor)=1000.
By the volt metre.
transformer max earth fault current
To calculate the no load current from transformer & core loss is also calculated.
if you know the gauge of the wire you can learn its current carrying capacity
the capacity of a transformer is defined as a product of voltage and current flowing through it.AS THE CURRENT IS MEASURED IN AMPERES AND VOLTAGE IN VOLTS, Hence transformers are measured/rated in KVA
The "current choking" means that the maximum capacity of a transformer is not being utilized. To prevent it from ever reaching its maximum capacity a lower value of over current protection or fuse is installed. The purpose is to use larger capacity transformer available but using smaller distribution and cables just sufficient for the application to lower the installation cost.
The product of the secondary rated current and the secondary rated voltage will give you the rated V.A of the transformer.
What should happen is that the circuit-breaker should trip to cut off the current before the transformer becomes damaged by overheating.
The primary current on a loaded transformer depends on the secondary current, which is determined by the load. So, if you know the secondary load current, then you can use the turns ratio of the transformer to determine the primary current:Ip/Is = Ns/Np
Without a load the secondary current is zero, by definition.
A transformer has a rating that is usually expressed in KVA. This is approximately a wattage rating. It is not dangerous but it can be the cause of some concern. An appliance has a set current that is draws. This current times the voltage is the appliance's wattage. The same goes for the transformer. It only has a certain capacity to supply a specific current that is governed by its KVA (watts). Driving the transformer beyond its rated capacity tends to heat the transformer beyond its working temperature. If left in this over current draw the transformer's windings insulation will break down and the windings will short circuit. This is usually the end of a working transformer. So short answer, more watts (amps) from appliance equals burned out transformer.