cable length multiply with the design current and multiply again by mV/A/m (check on site guide) then devide it by 1000. then u will get the volt drops. BY; MAMERGA
Depends on length. The more length, the more resistance.
5 megohms
Ohm's Law (V=IR) R=V/I=1
You should answer this question yourself by doing a couple of examples using Ohm's law I=E/R (current equals voltage divided by resistance. Here they are: Base circuit: 10 volt supply feeding a 10 ohm resistor calculate the current... New circuit: 10 volt supply (voltage kept constant) feeding a 20 ohm resistor (increased resistance) calculate the current... Did the current increase, or decrease? This way you can prove to yourself the answer!
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
A: Decreasing the current and/or the resistance
Look up in wire tables the resistance per ft for #6 wire (in ohms). Multiply by the total length of wire, 1500 ft because the current has to go through both wires. The answer is the total resistance of the cable. Then multiply by the current, 65 amps, and that's the volt-drop. In this example the total resistance is 0.59 ohms and the volt drop is 38.5 v. This cable can carry 65 amps but at this length the volt drop may be excessive and that is a reason for using a thicker conductor.
about 27ohms
Lost Volt refers to the amount of energy lost (in a battery, generally) to energy resistance of components. It is generally fairly negligible, but to calculate: V=IR where I is the current and R is resistance.
Depends on length. The more length, the more resistance.
The unit of resistance is the 'Ohm'. A conductor through which a current of 1 ampere produces a voltage drop of 1 volt has a resistance of 1 ohm.
3 volt bulb gives the biggest resistance
240 ohms
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
Answer for UK, Europe and countries running a 50 Hz supply service.You first calculate how much volt-drop can be allowed, say it's 6 volts on a 120 v supply, then divide that by the current, and it tells you how much resistance is allowed in the cable. Then look up a wire table that gives that amount of resistance for the length of wire you have. NB you have to double the length of wire because the current goes along one wire and back along the other.For example for a 6 volt drop with 15 amps your allowed resistance is 0.4 ohms If the distance is 500 feet you need wire that gives 0.4 ohms per 1000 ft. In that case the AWG wire table says that the wire needed is 6 AWG.Answer for USA, Canada and countries running a 60 Hz supply service.In North America the maximum voltage drop allowed is 3%. On 120 volts this would be 3.6 volts.A #3 copper conductor will limit the voltage drop to 3% or less when supplying 15 amps for 500 feet on a 120 volt system.
There is a 3.75 Volt drop across each bulb.
V=IR so, R=V/I or resistance = Voltage / Amps Therefore, the resistance (R) = 9 volts / 3 Amps answer: 3 Ohms