It depends on its cross-sectional area, its construction, and how it is laid.
Kilo Volts K = 1000 so 5KV = 5000 volts
Five kilovolts equals zero watts. The formula you need to use is W = A x V.
For a large manufacturing building of this size, I recommend using a combination of medium-voltage (MV) wiring for main distribution and low-voltage (LV) wiring for branch circuits. MV cables, such as those rated for 5kV to 35kV, can efficiently transmit power over long distances, minimizing losses. Additionally, ensure that the wiring is compliant with local electrical codes and standards, and consider using armored cables in areas with potential mechanical damage. Proper grounding and circuit protection measures should also be implemented to enhance safety and reliability.
The UK wire tables for 1.0 mm2 three-core domestic cable (live/neutral/earth) specify a limit of 10 amps.
It depends on how many volts there are.
5kV means 5 kilovolts or 5,000 volts. Electricity is analogous to water flowing through a pipe. Voltage is water pressure, current is water flow. Resistance is the resistance of the hose to the flow of water. The larger the hose, the less resistance and the more flow you can move with the least amount of pressure.
Kilo Volts K = 1000 so 5KV = 5000 volts
Five kilovolts equals zero watts. The formula you need to use is W = A x V.
The neutral wire is called a grounded conductor. It is also a current carrying conductor. It carries the unbalance current back to ground. At the substation the neutral is derived at the XO connection at the transformer. It needs to be grounded to earth. If not, you will have fluctuation of voltage on all phase wires to ground. With substations voltages being in access of 5kv in most cases. this fluctuation can be very vast.
A VERY BIG PROBLEM practically all electronics are restricted to voltages no greater 40 50 volts electrostatic can be as much as 5kv to 50 kv but the source impedance is very hi so while the voltage is there current capabilities are not a low impedance device can possibly survive these discharges but a hi impedance device like MOS cannot survive since the negligent current will raise the potential very hi blowing the device.
The k in kV stands for 1,000 and the v stands for volts. Divide 25,000 by 1,000 you get 25 kv.
It is a easy voltage to obtain and can check for breakover in the insulation. The voltage is higher then what would be put through most wire and shows any weakness.
Voltage rating usually refers to the insulation of the wire but could be terminology for electrical equipment also. In North America standard voltage ratings of wire are 300, 600, 1000, 5Kv, 15 Kv and 25 Kv.
7.5kVA is a value derived from the voltage multiplied by the current. Without knowing one, you cannot know the other. For example, think of the number 10kVA This could be made by :10kV * 1A or 5kV * 2A or 1kV * 10A or 2kV * 5A. You couldn't possibly know which is the initial pair.
Emf (voltage) =2p phi N Z divided by 60c p= no of pairs of poles phi = flux N =speed (rpm) Z = can't remember c = no. of parralel paths if you can make the values of the other parts of the formula such that the result is 5 kv your on this is initially a dc generator but can be made to apply to ac