yes because of bulb resistance :)
As the number of bulbs in a series circuit increases, the current decreases. As the number of bulbs in a parallel circuit increases, the current increases.
A: Adding any resistance bulbs or whatever in a series circuit will reduce current and will reduce total power. In this case the bulb will glow dimmer as any additional bulbs are placed in the series circuit. this is true if the same input source is kept constant.
In a series circuit, components (such as resistors, bulbs, or other devices) are connected end-to-end so that there is only one path for the current to flow. Because there is only one pathway for the current, the same current passes through each component in the circuit. This principle is derived from the conservation of electric charge. Since charge cannot accumulate or disappear in a closed circuit, the current that enters a component must be equal to the current that exits that component. In other words, the flow of current is continuous and consistent throughout the series circuit. Mathematically, this can be expressed as: I_total = I_1 = I_2 = I_3 = ... = I_n Where: I_total is the total current entering the series circuit. I_1, I_2, I_3, ..., I_n are the currents through each individual component in the circuit. It's important to note that while the current remains the same throughout a series circuit, the voltage (potential difference) across each component can vary depending on its resistance or impedance, according to Ohm's Law (V = I * R).
2 amps. If it is D.C.
All other light bulbs will turn off due to the series circuit being broken. The electrons cannot travel all the way through, hence the current will also not flow in the circuit, switching off all the other bulbs too.CommentIt's worth pointing out that the full supply voltage will then appear across the lamp holder -so take care!
the same current flows through both light bulbs
As the number of bulbs in a series circuit increases, the current decreases. As the number of bulbs in a parallel circuit increases, the current increases.
By adding more light bulbs
Since the SAME electrons have to go through both light bulbs, the current in both light bulbs will be the same (Kirchhoff's current law).
• In a parallel circuit, there are junctions in the circuit so the current can flow around the circuit in more than one way. • In a series circuit the current decreases as more bulbs are added. •In a parallel circuit, as more bulbs are added, the current increases. • This is because bulbs added in parallel offer less resistance
Bulbs in a parallel circuit draw the same amount of current, so each will display the same brightness. Bulbs in a series circuit share the current so all bulbs will appear dimmer.
3 amps each
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
It is unclear what type of circuit you are referring to, so I'll give both answers.parallel, current increases until too many bulbs have been added, then circuit breaker pops and current drops to zero.series, current decreases and all bulbs dim.
All the bulbs will go out. In a series circuit, the current at all points is the same. This is Kirchoff's Current Law. If you loosen or remove a bulb in a series circuit, the current at that bulb becomes zero, and by Kirchoff's Current Law, the current in every part of the circuit also becomes zero.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning