I think you probably mean is a neutral conductor necessary for a balanced star-connected load? If this is what you mean, then the answer is no, it isn't, as the phasor-sum of the phase currents will equal zero. Often, though, it is difficult to achieve a balanced load, so a neutral is then necessary, as it is needed to provide a return path for the unbalanced current -without this neutral, the phase voltages would change and become unbalanced.
By having a balanced load
The line wire will be hot and carrying power when the breaker is on. The load wire will not be hot and will have no voltage on it until it is connected with the line wire.
A balanced three phase load is where the current flowing in all three phases of the load are reasonably close to each other.Another answerWhen the voltage and measured current draw do not deviate by more than 2 percent under load.AnswerA balanced three-phase load is one in which each of the three loads is identical in all respects (magnitude and phase). Further to the first answer, the three line currents must not all be 'reasonably close', they must be identical -i.e. the same value and phase relationship.
If transformer then it refers to that, the primary is charged, but secondary is open, (no load is connected) If motor, it refers to that no load is connected to motor, the shaft is decoupled from the load, but running with out any load.
what is load line of transistor what is load line of transistor
The 'one wattmeter method' can only be used for balanced, wye-connected, loads where the load's neutral point is accessible. The wattmeter's current coil is inserted into any line conductor, and the voltage coil is connected between the same line and the neutral point. The wattmeter reading indicates the power of one phase, so the total power is three times the wattmeter reading.To measure the total power of a balanced or unbalanced wye- or delta-connected load, it is only necessary to use twowattmeters -this is called the 'two wattmeter method'. In this case, the current coils of each wattmeter are inserted into any two line conductors, and the voltage coils are connected between the two line conductors and the third line conductor. The sum of the two wattmeter readings will indicate the total power of the load.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
The hot wire is typically connected to the line terminal.
By having a balanced load
if it is balanced then neutral current is zero (!,e iR=iY=iB).AnswerFor both a balanced and an unbalanced load, the neutral current will be the phasor sum of the line currents.
The line wire will be hot and carrying power when the breaker is on. The load wire will not be hot and will have no voltage on it until it is connected with the line wire.
'Balanced loads' apply to three-phase a.c. loads. A three-phase kilowatt hour meter will measure both balanced and unbalanced loads, when correctly connected.
Formula for what?!
A phase current is the current passing through a phase, whereas a line current is the current flowing through a line.In the case of a balanced delta-connected load, IL = 1.732 IP. In the case of a balanced star-connected load, IL = IP.For unbalanced loads, these relationships don't hold true, and must be individually calculated.
In a light switch circuit, the line is the wire that brings power into the switch, while the load is the wire that carries power from the switch to the light fixture. The line wire is typically connected to the power source, while the load wire is connected to the light fixture.
In electrical systems, the load wire carries the electrical current to the device being powered, while the line wire brings the current into the system from the power source. The load wire is typically connected to the device, while the line wire is connected to the power source.
Do you mean 'per phase' or do you mean 'per line'? The conductors that connect a three-phase supply to its load are called 'lines' not 'phases'. If you mean 'per line', and the load is balanced, then you can manipulate the following equation to make the line current (IL) the subject: power = 1.732 EL IL (where EL = line voltage = 380 V) If you really DO mean 'per phase', then it's necessary for you to specify whether the load is star (wye) or delta connected.