All AC voltages and currents are expressed as rms values, unless otherwise specified. So 120 V AC is an rms value.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
"Voltage peak" is generally used to denote the maximum(amplitude) of AC voltage supply. It can not be approximated as dc value. The closest approximation one can make for dc value of a ac supply is the RMS(root mean square) value of the voltage. So that the ohmic loss caused by the given AC voltage supply is equivalent to that caused by a dc supply having value equal to the RMS of this AC supply (for given impedance & time).
Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".Answer'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.
Simply multiply the peak voltage to 2 and you will get the peak to peak voltage.
P-P voltage = RMS voltage * 2 * sqrt (2)Here's an example: house voltage is 120VRMS, which is actually ~169 volts peak - neutral. double this will give peak to peak value.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does
To find the root mean square (rms) value for a voltage given in peak-to-peak (Vpp), you need to divide the Vpp value by 2√2. In this case, the Vpp is 300mV, which is equivalent to 0.3V. Dividing 0.3V by 2√2 ≈ 2.828, the rms value is approximately 0.106 V.
For a 12V peak voltage (V_peak), the peak-to-peak value (V_pp) is 24V, as it is twice the peak voltage (V_pp = 2 * V_peak). The root mean square (RMS) value is approximately 8.49V, calculated as V_rms = V_peak / √2. The half-cycle average voltage is about 7.64V, calculated as V_avg = (V_peak / π).
Use an oscilloscope. That shows the voltage waveform and you can read the peak value.
The quoted value is usually RMS value, i.e it is lesser than the peak value of the voltage, therefore the peak value is sqrt(2) times the quoted value. (it is a sine wave)
Peak value is 1.414 times the RMS voltage. On a 240 volt circuit the peak voltage is 240 x 1.414 = 339.36 volts. The peak to peak value is twice this.
"Voltage peak" is generally used to denote the maximum(amplitude) of AC voltage supply. It can not be approximated as dc value. The closest approximation one can make for dc value of a ac supply is the RMS(root mean square) value of the voltage. So that the ohmic loss caused by the given AC voltage supply is equivalent to that caused by a dc supply having value equal to the RMS of this AC supply (for given impedance & time).
Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".Answer'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.
100v divided by 1.41
Unless otherwise stated, the value of an a.c. current or voltage is expressed in r.m.s. (root mean square) values which, for a sinusoidal waveform, is 0.707 times their peak value. The output of a voltage (or potential) transformer is no different, its measured voltage will be its r.m.s value which is lower than its peak value.