depending on the stray capacitance it can be from a few ten volts to a few kilo volts.
Maximum induced voltage occurs when the current is changing at its greatest rate -this occurs when the current passes through zero. Since this voltage acts to oppose current flow, this maximum voltage acts in the negative sense when the current is acting in the positive direction. Since the supply voltage is equal, but opposite, the induced voltage, it is maximum when the current is zero -so leads by 90 degrees.
In an ideal inductor, no, there is no voltage induced across an inductor unless the current in the inductor is changing. However, since there are no ideal inductors nor power supplies, eventually an inductor will draw a constant current, i.e. the limit of the power supply; and, since no inductor has zero ohms at equilibrium, that current will translate to voltage.
voltage across inductor create a flux. because of variation current developes an opposite emf.
due to change in flux
When current flows through an inductor, a magnetic field is created. That's the simple explanation. More formally, an inductor is a magnetic device that reactively resists a change in current by presenting a voltage backwards towards the source. The equation for an inductor is ... di/dt = v/L ... which means the the rate of change in current in amperes per second is proportional to voltage in volts and inversely proportional to inductance in henrys. Theoretically, this means that, if you place a constant voltage across an inductor, current will linearly increase without bounds to infinity. Practically, this will be limited by resistance and current capacity.
How do you propose to connect a decreasing current to the inductor ? The initial current through the inductor is zero, and you want to connect it to a current which is not zero and decreasing. At the instant you make the connection, the inductor current is zero, and it must rise to the non-zero value where you want it to begin decreasing. The current in the inductor cannot change from zero to something in zero time. As it rises from zero to the initial value, guess what . . . the inductor is storing energy in its magnetic field, while producing the usual voltage equal to [ L di/dt ].
The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.
Maximum induced voltage occurs when the current is changing at its greatest rate -this occurs when the current passes through zero. Since this voltage acts to oppose current flow, this maximum voltage acts in the negative sense when the current is acting in the positive direction. Since the supply voltage is equal, but opposite, the induced voltage, it is maximum when the current is zero -so leads by 90 degrees.
In an ideal inductor, no, there is no voltage induced across an inductor unless the current in the inductor is changing. However, since there are no ideal inductors nor power supplies, eventually an inductor will draw a constant current, i.e. the limit of the power supply; and, since no inductor has zero ohms at equilibrium, that current will translate to voltage.
Eli the ice man. Voltage (E) before Current (I) in a coil (inductor)(L) Current (I) before Voltage (E) in a Cap. (C) Got it?
In a perfect inductor (one with no series internal resistance), the current lags the voltage by 90 degrees. If the inductor has series internal resistance, then the current will lag the voltage by less than 90 degrees - the more the resistance in series with the inductor, the smaller the angle. The tangent of the angle can be found from the ratio of the inductive reactance of the inductor to the DC resistance of the inductor. That is, Tan (phase angle) = (2 x pi x frequency (Hz) x inductance (H)) divided by resistance (ohms) eg, a 1 henry, 100 ohm inductor on 60Hz would give: (2 x pi x 60 x 1) / 100 = 3.77; tan-1(3.77) gives 75 degrees lag of current behind voltage. The cosine of this angle gives the 'power factor' for the inductor - that is, the amount of useful energy dissipated in the inductor. Cos 75 is about 0.25 - so 25% of the energy actually does useful work (heat) - the rest of the energy (75%) is returned to the supply mains when the inductor discharges its magnetic field.
voltage across inductor create a flux. because of variation current developes an opposite emf.
Because of Ac supply, current lags voltage by 90 in Inductor.
Yes, an inductor works with direct current. It is called an electromagnet. Of course, a practical electromagnet has series resistance, otherwise the current in the inductor would increase to the limit of the current/voltage source.
Voltage leads current or, more specifically current lags voltage, in an inductive circuit. This is because an inductor resists a change in current.
With a series RLC circuit the same current goes through all three components. The reactance of the capacitor and inductor are equal and opposite at the resonant frequency, so they cancel out and the supply voltage appears across the resistor. This means that the current is at its maximum, but that current, flowing through the inductor and the capacitor, produces a voltage across each that is equal to the current times the reactance. The voltage magnification is the 'Q factor', equal to the reactance divided by the resistance.
due to change in flux