Ohm's Law: Voltage is current times resistance, so 0.5 A through 4700 Ohms is 2350 volts. Power Law: Power is voltage times current, so 2350 volts times 0.5 A is 1175 watts.
WARNING: This is both high voltage and high power. Do not attempt to duplicate this in the lab without adequate protection and appropriate components.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
Because if high resistance is like kilo mega ohm is used , corresponding current through the balanced point is in the order of micro ampere, so you have to use micro ampere sensitive ammeter , otherwise normal ammeter always show zero reading
20k is equal to 20,000 ohms (20 kilo ohms) and 200k is equal to 200,000 ohms (200 kilo ohms) of electrical resistance
The secondary winding's current rating is the rated apparent power of the transformer (expressed in volt amperes) divided by its voltage rating (expressed in volts). This applies to both step down, and step up, transformers.
K = kilo = 1000's V = volts AC = alternating current So, 12 KVAC is 12,000 volts of alternating current
ANSWERS; Transparent
10.2 kilo ohms is the resistance necessary for 1 volt to induce a current of 98.04 micro amperes. Ohm's law: voltage equals current times resistance.
If the generator is delivering 100 KW of power and the Voltage is 10 KV, then it's supplying current atI = P/E = (100,000/10,000) = 10 Amperes.If 10A is flowing through cable with a total resistance of 5 ohms, the power dissipated by the cable isP = I2R = (10)2 x (5) = 500 watts.Nice problem !
10.2 kilo ohms is the resistance necessary for 1 volt to induce a current of 98.04 micro amperes. Ohm's law: voltage equals current times resistance.
A "kilo" means 1000. So a kilowatt is a thousand watts. The same applies to voltage. A kilovolt is 1000 volts. Wattage is the measurement of "electrical power". Voltage is the measurement of "electrical potential" See "Ohms Laws" for more explanation of electrical terms.'
With one amp of current flowing there would be 5500 kilowatts of power. With other amounts of current, multiply by the current.
100 kilo ohm resistance can not kill you since resistance is a measure of the resistivity property of an object, it resist the passing of current. However, when that object is supplied by a power source of at least 0.1 Ampere you can feel the current. At least 0.02 ampere current rating is dangerous already. 20 to 75 milliamps is very dangerous, more than that can damage heart or else lead to death.
Ohm's law: Current = voltage divided by resistance240 volts divided by 0.2 ohms = 4,800 amperes.1,152,000 watts, by the way, so don't even think about trying it.
By Ohm's law, voltage = current times resistance, so 50 mA of current through a 4.7 kOhm resistor yields a voltage drop of 235 volts.By the power law, power = voltage times current, so 50 mA of current and 235 volts yields a power of 11.75 watts.That is quite a bit of power, so the resistor is going to become very hot, and must be rated for that power, otherwise it will self-destruct and/or cause a fire.AnswerAn alternative, and quicker, method of solving this problem would be to simply to use the following equation:P = I2RIn which case:P = (58 x 10-3)2 x (4.7 x 103) = 15.81 W (Answer)(***The original answer used 50 mA, rather than 58 mA, by mistake.)
Yes. Because the 30v ac is root-mean square value which is the value of an alternating quantity that will produce the same heating effect as the DC quantity when applied to the same resistance.
Resistance is constant no matter the frequency applied. Reactance varies depending on the frequency of the power applied to it.
V= I x R Therefore; .00005 x 52,000 = 2.6 volts