I = E ÷ R = 120V ÷ (60Ω + 40Ω + 20Ω) = you figure it out now
Resistors are wired in series when they are connected in a line. The current flows through the resistors one after the other.
Which is true of a series circuit that has two resistors?A.The resistors are on different branches of the circuit.B.Neither resistor has current flowing through it.C.One resistor has no voltage across it.D.Both resistors have current flowing through them.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
adding resistors to a string will have the effect of decreasing each resistor voltage drop.
a voltage source has very less(negligible)resistance.thus is considered as a short.if connected in parallel to a resistor will draw all the current acting as a short.thus is always connected in series of a resistor.where as a current source has tremendous resistance(infinity).thus if connected in series will be conidered as an open branch and no current will flow through it other than the source current.
The resistors connected in single path are called series resistances or resistances in series.The current across both the resistors is same while the potential differences are different.
Resistors are wired in series when they are connected in a line. The current flows through the resistors one after the other.
It depends upon the connection of the resistors, if the resistors are connected in parallel then the voltage is same where as in case of resistors connected in series the voltage is different across different resistors.
if resistors connected in series the resistance will increase.Then it limit the flow of current through it. voltage may be increased. A: by connecting any resistors in series it will limit the current flow it will effect the current but never the voltage applied
yes two resistors can connect both in series and parallel because when you connect two resistors in a closed loop, the same intensity of current flows across them and also they are connected to the same nodes which are the conditions for series and parallel connections respectively.
Which is true of a series circuit that has two resistors?A.The resistors are on different branches of the circuit.B.Neither resistor has current flowing through it.C.One resistor has no voltage across it.D.Both resistors have current flowing through them.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
Because, in series connection the current is same in all resistors, so the ammeter deflection for finding current is same in each ammeter.
A Discussion has been started about this question. Click on the View Discussion button below to take part in it.The "type" of a source does not limit in what ways resistors can be connected to it. Resistors can be connected either in series or in parallel - or in a combination of series and parallel - across a voltage source.Similarly, resistors can be connected either in series or in parallel - or in a combination of series and parallel - across a current source.
It depends on the power rating of the resistors. The total power of a series or parallel combination of resistors is the sum of the power rating of each. Here is one possible answer that assumes the resistors are rated at 1/4 watt and are connected in series. Power = Current ^ 2 x Resistance. The ^ means squared. Current = square root (Power / Resistance) Current = square root (0.25 / 50) = 0.0707 amps The total power of the three resistors in series is 0.25 x 3 = 0.75 watts Current = square root (0.75 / 150) = 0.0707 amps <-- Notice you get the same current as before. This must be true because the current flowing through a series circuit is the same in each component. Since Voltage = Current x Resistance Voltage = 0.0707 x 50 = 3.54 volts across one of the resistors OR Voltage = 0.0707 x 150 = 10.61 volts across the series combination. Here's another way to calculate the answer. Voltage = square root of (Power x Resistance) Voltage = square root (0.25 x 50) Voltage = 3.54 volts This is the maximum voltage across one of the resistors. If the three resistors are connected in series, the total resistance would be 150 ohms and the maximum voltage across the series combination would be 3.54 x 3 = 10.61 volts. If the resistors are connected in parallel, the equivalent resistance is 16.67 ohms. Since the voltage across parallel resistors is the same, the maximum voltage for three 1/4 watt resistors would be square root (0.75 x 16.67) = 3.54 volts. This is the same answer calculated for the resistors in series. The maximum current through each resistor is V / R = 3.54 / 50 = 0.0707 amps or the same current as the series combination. However, in this case, the total current flowing through the parallel combination is 0.0707 x 3 = 0.2121 amps and Power = I ^ 2 x R = .2121 ^ 2 x 16.67 = 0.75W. This proves that the powers add no matter if the resistors are in series or parallel. If the resistors are rated at 1/2 watt the maximum voltage across one resistor is 5 V and the maximum across the series combination is 15 V. The maximum current is 0.1 A.
Four 1000 ohm resistors in series have an effective resistance of 4000 ohms. Across a 4 volt voltage source, they would have a current of 1 mA, with a power dissipation of 4mW.
A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source.