It depends if the are in series or parallel.
In series: 55K ohms
In parallel: 5K ohms
It really all depends brah.
If they are in series, you need to add the resistance values.
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
The current in the circuit will depend on how the three resistors are wired. Series? Parallel? Series parallel? With the resistors in series, 3, 2 and 4 ohms will add to 9 ohms. As I = E/R, I = 9 V / 9 ohms = 1 A. With the resistors in parallel, the 3, 2 and 4 ohm resistors will draw 3 A, 4.5 A and 2.25 A respectively, and the total current will be the sum of the branch currents, or 3 A + 4.5 A + 2.25 A = 9.75 A. There are 3 different series parallel circuits possible, and more investigation will be necessary to solve for them.
50 ohms
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
28 + 56 = 84 ohms
30 ohms
Resistors placed in series create a total resistance that is found by simply adding the values of the resistors. (Knowing the applied voltage isn't necessary to solve this problem.) Rt = R1 + R2 + R3 = 2 ohms + 4 ohms + 6 ohms = 12 ohms
If they are in series, you need to add the resistance values.
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
400 ohms
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
The equivalent resistance of resistors connected in series is simply the sum of their individual resistances. Therefore, the equivalent resistance of three 8.0-W resistors connected in series is 24.0 W.
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.