A: nothing should happen since a 1N4001 is capable to sustain 100v in the reverse direction. 52v is within the 100v reverse breakdown voltage.
There will be no "average" reverse breakdown voltage. When the applied voltage reaches 3.3v, the 3.3v zener will conduct and the voltage will go no higher. The 5v zener will never conduct because the voltage across it will never go higher than 3.3v The only way the 5 volt zener will ever conduct is if the 3.3v zener fails. ALAN H.
They are usually used as voltage variable capacitors,not as diodes. The diode is made in such a way that when reverse biased (where the voltage across the diode is in the polarity where very little current flows) the capacitance varies considerably with the voltage across it. This action is usually used to make resonant Inductor-capacitor circuits have their resonant frequency dependent upon the "DC" voltage across them. For instance: A low frequncy signal, like Audio, is impressed across a veractor tuned resonant circuit to make a much higher frequency oscillator (at say an FM station frequency) vary its frequency in proportion to the amplitude of the "instantaneous" Audio signal. (at 100 MHz nominal oscillation frequency, the audio is like slowly moving "DC"). One can make a frequency modulated radio this way. (rather distorted; veractor characteristics of V across to C across are pretty non-linear).These diodes are made by having one side of the "P-N" junction that forms the diode be very lightly doped. What this does is make the depletion region; the region where conductive carriers are pulled out by the reverse bias across the diode (where it doesn't conduct) change its width considerably more than usual. (all diodes have some of this voltage variability) This depletion width is non-conducting and acts like the dielectric of a capacitor. As the voltage across changes the width of the dielectric changes thus the capacitance across the device changes.
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.
voltage across inductor create a flux. because of variation current developes an opposite emf.
The zener region describes the area on the performance curve (a graph of voltage across versus current through the junction) of a zener diode. The diode acts like a "regular" diode in the forward biased direction. When some 0.7 volts or so is reached, forward current begins to climb rapidly as voltage is increased (for silicon diodes.) But in the reverse direction recall that as the diode is reverse biased, a small amount of current will flow (because of minority carriers). This "trickle" of current will continue until the "zener voltage" is reached, and then the diode will begin to conduct heavily. On the graph, this is the zener region. Zener diodes can be made to breakdown at a specific voltage, and their ability to conduct reverse current can be increased by manufacturing a larger diode. That means there are a range of voltages and wattages of zener diodes available. Wikipedia has more information and that graph. Use the link provided to get there.
Voltage is impressed across a circuit. Current flows through a circuit.
Reverse voltage is voltage is applied in reverse. Instead of the positive voltage going into the anode lead of a component, it goes into the cathode lead of the component.
Zener diodes are special types of diodes that can maintain a constant voltage across their terminals when they are reverse-biased. This property allows them to regulate voltage in electronic circuits by conducting current in the reverse direction when the voltage exceeds a certain threshold, effectively stabilizing the voltage across the circuit.
A: 1/7
A: LEDS are basically a diodes.So yes they can be strung right across the AC line. Unfortunately the reverse voltage is very low and tend to leak at hi voltage. the design should provide protection for the reverse voltage with resistance across each to equalize the leakage current otherwise it will work only once.
In a parallel circuit, Voltage is constant through out the circuit. Thus, the voltage across each lamp is 6-volts.
A zener diode has a relatively constant reverse voltage, at the designated zener voltage. If you had a circuit, say, with an AC source, a resistor, and a zener, the waveform across the zener would be the AC source, clipped at the reverse bias zener voltage, and clipped again at the forward bias voltage, typically about 0.7 V.
The device that increases or decreases the voltage impressed across a power line is known as a voltage regulator. A voltage regulator is a type of transformer where the primary and secondary turns ratio are fairly close; one (primary or secondary) often has a tap changing ability to add or remove several windings, allowing more dynamic control of voltage.
Capacitors can pass alternating current provided the current and the voltage are within the capacitor's rating. Very often there is a dc bias voltage across the capacitor as well as the ac voltage, so the peak voltage must not exceed the limit. Electrolytic capacitors must not have a reverse voltage across them in any circumstances, because this can cause failure.
-- The definition of 'reverse bias' is anode negative with respect to the cathode, or negative voltage across the diode. That places the graph in negative-x territory. -- The diode simply acts as a resistor. Its unique 'diode' characteristics arise from the fact that its 'resistance' changes with different bias points, but the current through it always has the same polarity as the voltage across it. Therefor . . . -- When the voltage across it is negative, the current through it is also negative. Negative current appears on the graph in negative-y territory. -- Negative-x territory/negative-y territory is the third quadrant.
piv:the maximum value of reverse voltage across a diode that occurs at the peak of the input cycle when the diode is reversed-biased.
what can be inferred about the voltage across the bulb