Root mean square (average ***) voltage
Because ac (alternating current) does not warm up a lamp, heater, etc. as well as a direct current of the same value as the peak ac, we need to work out how to find the equivalent dc (direct current) voltage for the ac situation.
The r.m.s. value of an alternating current or voltage is the value of direct current or voltage which produces the same heating effect.
For a sine wave, the r.m.s. value is 0.707 times the peak value, or, conversely, the peak value is 1.414 times the r.m.s. value.
Peak voltage
Peak voltage is measured from the zero axis to the top of the curve. So, in the case of the UK mains supply, where the average r.m.s. voltage is 230 volts, Vpeak = √2 x Vrms = √2 x 230 V = 325.22 volts.
Note: The average voltage is always zero.
*** The average value and the r.m.s. value of a sine wave are not the same thing. The average value of a sine wave is 0.636 x the peak value.
Calculating the Root Mean Square (RMS) is a messy task. However, the humane way to do it is to multiply the Peak value of a sine wave by .707. That will take you directly to the RMS value.
rms. dat means Vp-p will be 325V.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
okay, where's the "given waveform"?
All AC voltages and currents are expressed as rms values, unless otherwise specified. So 120 V AC is an rms value.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
RMS is just 15/sqr2 average is 15 * 0.637
rms. dat means Vp-p will be 325V.
When you say holdhold supply of 230volts, you are referring to the RMS value, not the peak value.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
A square wave has the highest RMS value. RMS value is simply root-mean-square, and since the square wave spends all of its time at one or the other peak value, then the RMS value is simply the peak value. If you want to quantify the RMS value of other waveforms, then you need to take the RMS of a series of equally spaced samples. You can use calculus to do this, or, for certain waveforms, you can use Cartwright, Kenneth V. 2007. In summary, the RMS value of a square wave of peak value a is a; the RMS value of a sine wave of peak value a is a divided by square root of 2; and the RMS value of a sawtooth wave of peak value a is a divided by cube root of 3; so, in order of decreasing RMS value, you have the square wave, the sine wave, and the sawtooth wave. For more information, please see the Related Link below.
okay, where's the "given waveform"?
rms value is measured using voltmeter with the use of heat sensing elements.
AC RMS Value x 1.414
All AC voltages and currents are expressed as rms values, unless otherwise specified. So 120 V AC is an rms value.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
You don't need exactly one cycle data for computing the RMS value. It is just a convenient normalization. 1 cycle = 1Hz. RMS values can also be specified in 1 Mcycle, 1kcycle, even 2.39384kcycles. Again, 1 cycle is simply convenient. In other words, if the RMS value were specified in MHz, the RMS value will be 20*log(MHz/Hz) higher.
Its 0.7 times peak-0 voltage, 106 mv RMS.