A motor that is rated at 250 full load amps will need 400 amp time delay fuses or a 500 amp frame breaker with adjustable amperage trips. The wire size for this motor has to be 125% of the motors FLA. 250 x 125% = 312 amps. A 350 MCM copper conductor with an insulation factor of 90 degrees C is rated at 325 amps.
125 percent of full current rating of the motor
At 600 volts the rule of thumb is one amp per horsepower. So a 20 HP motor would need 20 amp wire. The code book states that a 20 HP motor at 575 volts draws 22 amps. The conductor for a motor has to be 125% rating of the motors FLA (full load amps). 22 x 125% = 27.5 amps. A #10 copper conductor with a insulation factor of 60,75 or 90 degrees C is rated at 30 amps.
The formula you are looking for is I = kW x 1000/1.73 x E x pf. I = 1.5 x 1000 = 1500. 1500/1.73 x 400 x .86 = 1500/595 = 2.5 amps. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. A feeder for a motor has to be rated at 125% of the motors full load amps 2.5 x 125% = 3.1 amps A #14 copper conductor with an insulation rating of 90 degrees C is rated at 15 amps.
A three phase 30 HP at 240 volts draws 80 amps. Motor feeders have to be rated at 125% of the motors full load amps. 80 x 125% = 100 amps. A # 3 copper conductor with an insulation factor of 75 or 90 degrees C are rated at 100 and 105 amps respectively. Non-time delay fusing is 225 amps, time delay fusing is 125 amps and a circuit breaker is sized by 250% x 80, the full load amps, which equals 200 amps.
Of course TMX 125 is much more faster i believe coz thats my favorite motor.
The Electric Company - 1971 125 1-125 was released on: USA: 14 April 1972
The current draw is about 27 amps. A motor feeder has to be 125% of the motors full load amperage. 27 x 125% = 33 amps. A #8 copper conductor with an insulation factor of 90 degrees C is rated at 40 amps.
125 hp and 107 ft lbs of torque.
the single cam motor has about 100 hp abd the dohc has about 125 hp.
The North American electrical code states that a conductor for a motor must be rated at 125% of the motor's full load amperage. 125% x 50 = 63 amps. A #6 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 65 amps respectively.
The Electric Company - 1971 385 3-125 was released on: USA: 12 April 1974
The Electric Company - 1971 125B 6-125 was released on: USA: 8 April 1977
The Electric Company - 1971 515 4-125 was released on: USA: 11 April 1975
Motor oil
1971
T430.247 of the NEC shows that a 1 hp motor operating at full load on 115v will draw 16 amps, called Full Load Current (FLC). Conductors supplying this motor are required to be 125% of FLC which is 20 amps. Motor circuits are complicated things and do not follow the rules of other circuits. This motor, while drawing a maximum of 16 amps at full load and supplied with #12 AWG copper conductors can be protected by a breaker of 40 amps.