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Why the index of an array be a positive number?
Since an array cannot contain a negative number of items, the size of an array must be at least 0. So if you ever tried to retrieve the element at a negative index in an array, it would automatically be understood to be out-of-bounds.
What is the index number of the last element of an array with 9 elements?
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
How will you find the location of an element of an array?
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
What do array subscripts always have?
Array subscripts always have a zero-based index. In languages that allow an n-based index, the index is simply offset by n elements, so the compiler subtracts n from the given index to obtain the zero-based index. Arrays are always zero-based because the first element of an array is found zero elements from the start of the array.
How can you fix an ArrayIndexOutOfBoundsException in java?
This is very common exception and name of the exception class tells exactly what kind of problem you have. If you would look into stack trace, which should have been generated too you would be able to find exact place where it happened. The problem is that "Array Index Out Of Bounds". This means that you used index on array which is invalid. That could negative number, because all arrays starts from 0. If you array has N items and you will try to get item with index N or higher you will get this exception too. Only available indexes are from 0 to N - 1, where 0 points to the first item and N - 1 to the last one.
Why the index of an array be a positive number?
Since an array cannot contain a negative number of items, the size of an array must be at least 0. So if you ever tried to retrieve the element at a negative index in an array, it would automatically be understood to be out-of-bounds.
Why the array is starting from zero?
By design; it makes the compiler's work easier. 1-based array's addressing-function: Address (array, index) = Address (array) + (index-1)*Elemsize(array) 0-based array's addressing-function: Address (array, index) = Address (array) + index*Elemsize (array)
How you use negative index in array?
You cannot do this easily in C programming. Arrays in C always start with index 0. If you must use a negative array index, you can do that by allocating an array, and then pointing to an element within the array. Say you allocate an array 10 ints long, named a; then set b = &a[5]. Then b[-4] = a[1]. However, this is extremely bad programming practice and is almost certain to cause data corruption. Some compilers will treat array indices as unsigned, also, so that when you specify b[-4], the compiler will internally simplify that to b[65532] and your program will crash.
What is the relationship between the value of the subscript and the value of the array element in c?
You can access the array-element via index (or subscript), but it is not possible the other way around.
What is the index number of the last element of an array with 9 elements?
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
What is difference between key and index in php arrays?
A key is the name of a variable in an array ($array["key"]) and the index is the position it's at ($array = ["key" => 0], the index would be 0). Keys and indices are the same if the array is not associative though ($array = [true], the key holding the value true is named 0 and is at index 0).
What is the negative prefix of array?
The negative prefix of "array" would be "non-".
How will you find the location of an element of an array?
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
What do array subscripts always have?
Array subscripts always have a zero-based index. In languages that allow an n-based index, the index is simply offset by n elements, so the compiler subtracts n from the given index to obtain the zero-based index. Arrays are always zero-based because the first element of an array is found zero elements from the start of the array.
How do you access last index of an array if the size is set during run time?
For an array of length s, the last element has index s-1.
How can you fix an ArrayIndexOutOfBoundsException in java?
This is very common exception and name of the exception class tells exactly what kind of problem you have. If you would look into stack trace, which should have been generated too you would be able to find exact place where it happened. The problem is that "Array Index Out Of Bounds". This means that you used index on array which is invalid. That could negative number, because all arrays starts from 0. If you array has N items and you will try to get item with index N or higher you will get this exception too. Only available indexes are from 0 to N - 1, where 0 points to the first item and N - 1 to the last one.
How do you find particular element in array?
by using index position we can find the particular element in array.
