Combining resistors and capacitors in a circuit creates an RC circuit, which can influence the circuit's behavior over time, particularly in terms of charging and discharging rates. The resistor controls the flow of current, while the capacitor stores and releases energy. This combination results in a time-dependent response characterized by exponential voltage changes, which can be used in applications like filters, timers, and oscillators. Overall, the interaction between resistors and capacitors determines the circuit's frequency response and transient behavior.
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
Miller's theorem is used in circuit analysis to simplify the calculation of equivalent capacitance or resistance in feedback circuits. It states that a voltage-controlled voltage source can be replaced by two capacitors (or resistors) when considering the input and output nodes, effectively isolating the feedback effect. This simplification allows for easier analysis of complex circuits by reducing the number of elements to consider, particularly in amplifiers and oscillators. By applying Miller's theorem, engineers can more readily predict circuit behavior, especially in high-frequency applications.
The Ferranti effect is reduced by using shunt reactors and series capacitors.
A: One example is the gain of an op amp the gain is strictly related to resistors in a closed loop. The gain will change % wise as the resistor change % wise
The major problem with resistors at high frequencies is for wire-wound (power) resistors, that will act as inductors at high frequencies. In addition, very small resistors, like chip resistors, can also exhibit capacitive effects. Special high frequency resistors are designed to offset these effect.[1]
Capacitors in parallel simply add up, similar to resistors in series... CTOTAL = sumI=1-N (CI) Capacitors in series work like resistors in parallel... CTOTAL = 1 / sumI=1-N (1 / CI)
As I have no information on the circuit I can make no valid predictions as to the effect of replacing diodes with resistors. However I assume the effect(s) will resemble that of having very defective diodes in the circuit.
Sure some resistors are wire wound chrome wire and as such will display an inductance characteristics
Its no longer a rectifier and the resistors may catch fire.
The equivalent resistance is the overall effect all of the resistances in a circuit has. Put another way, it is the value a single resistor in a circuit would have to be in order to have the same effect as all of the resistors resistors combined in a given circuit.
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
Miller's theorem is used in circuit analysis to simplify the calculation of equivalent capacitance or resistance in feedback circuits. It states that a voltage-controlled voltage source can be replaced by two capacitors (or resistors) when considering the input and output nodes, effectively isolating the feedback effect. This simplification allows for easier analysis of complex circuits by reducing the number of elements to consider, particularly in amplifiers and oscillators. By applying Miller's theorem, engineers can more readily predict circuit behavior, especially in high-frequency applications.
C. L. Hanks has written: 'Report on the effect of nuclear radiation on capacitors' -- subject(s): Capacitors, Effect of radiation on
The voltage supplying the circuit will be divided across the series resistors in proportion to their resistance. The wattage of the resistors has no effect on the distribution, but if you put an under rated resistor in the circuit, it will fail. For example, if you have a 10v source, and a 1 ohm resistor in series with a 3 ohm resistor, the 1 ohm resistor, being only a quarter of the total resistance, will see a quarter of the voltage, or 2.5 volts. The other 7.5 volts will seen across the 3 ohm resistor. The total power consumed by the circuit is given by P = VI or V2/R or I2R, so for this circuit, the resistors will consume 25 watts (current is 10/4 = 2.5 amps according to Ohms Law), and 10 x 12.5 gives 25 watts. Hope that helps ItAintMe
I must tell you that I've been building, troubleshooting, and studying electronics (in that order) for more than a half century, and this is the first time I have ever encountered the concept of a "diagonal resistor". I really should let this question pass, because I really have no idea what it means. But I'm somehow drawn to it. At the frequencies of devices that even use discrete resistors any more, the physical position and orientation of the resistors has no effect on their electrical characteristics or performance in the circuit. If the position mattered, then there would be a big red "THIS END UP" arrow on every transistor radio and boombox. And if, by chance, you're referring to the presentation of resistors on electrical schematic diagrams, please relax. The arrangement of the components and their symbols on the schematic is completely a matter of making a clear drawing, and has absolutely no relationship to their physical arrangement in the circuit when it's constructed. At least not until you get into microwave devices, and at that point, trust me, you and I would not even recognize a resistor in the circuit if we were looking at one.
It doesn't necessarily have a 'function'; it is simply the natural consequence of applying a potential difference across a conductor. However, this is usually done for a reason, and its function is then derived from one or other of the three effects of that current:heating effect -e.g. electric heatersmagnetic effect -e.g. electric motorschemical effect -e.g. electrolysis (electroplating)
The Ferranti effect is reduced by using shunt reactors and series capacitors.