Voltage is current times resistance, 1.2 x 110 = 132 volts.
Typically resistance rises with temperature.
Yes, voltage effects the output of electric heaters. The wattage output rating of the heater will not be reached due to the lower applied voltage. For example if the heater is 5000 watts at 277 volts, the current is I = W/E 5000/277 = 18 amps. The resistance of the heater is R = W/I (squared) = 5000/18 x 18 (324) = 15.43 ohms. Applying 220 volts on the same heater whose resistance is 15.43 ohms results in this new heater wattage rating. W = E (squared)/R = 220 x 220 (48400)/15.43 = 3137 watts. W = watts, I = amperage, R = resistance in ohms and E = voltage.
The equation you are looking for is R = E/I.
The formula you are looking for is W = E(squared)/R, W = Voltage (squared) divided by Resistance.
Yes it would be unlikely an electric motor coincidentally exactly matched the resistance of an electric heater.
There are heater-resistance wires in the glass of the back windshield.
Voltage is current times resistance, 1.2 x 110 = 132 volts.
In an electrical space heater, electrical current dissipates energy into heat, and the heat radiates from the element. In a fuel powered space heater, an orifice throttles the fuel feed (resistance to flow), which controls the heating rate. In a steam powered space heater, an orifice throttles the steam (resistance to flow), which controls the heating rate.
Typically resistance rises with temperature.
Typically resistance rises with temperature.
A 1000 W heater would have more resistance compared to a 100 W bulb. The higher the power rating of an electrical device, the lower its resistance, as resistance is inversely proportional to power. So, the 1000 W heater would have lower resistance than the 100 W bulb.
The resistance that controls a heater motor in the electric system .
The resistance of the electric heater will increase by approximately 56.25% (25% increase in length results in a 56.25% increase in resistance). This relationship is given by the formula: new resistance = (1 + 0.25)^2.
check the heater control valve it should be 10 ohms of resistance
4.12A. V=IR
Check the back of the heater switch. The electrical plug may be having an melt down from resistance.