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It is a 1-1/2 ton: 18000 BTU (unit size)/12,000 BTU (per ton)=1.5

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What is the Armstrong air conditioner model number SCU10E30A-2 tonnage?

Looks to me like 30,000 BTU or 2 Tons of cooling @400 CFM per Ton


What is amstrong number?

153 is a Armstrong number 13+53+33=153


Write a java program to check a number is Armstrong number?

import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }


To find Armstrong number in java?

/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }


Write a c program to find Armstrong number using ifstatement?

#include<stdio.h> int main(){ int num,r,sum,temp; int min,max; printf("Enter the minimum range: "); scanf("%d",&min); printf("Enter the maximum range: "); scanf("%d",&max); printf("Armstrong numbers in given range are: "); for(num=min;num<=max;num++){ temp=num; sum = 0; while(temp!=0){ r=temp%10; temp=temp/10; sum=sum+(r*r*r); } if(sum==num) printf("%d ",num); } return 0; }

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The Armstrong air conditioner model number SCU10B18A-1A has a tonnage of 1.5 tons. This model is designed for residential applications and is part of Armstrong's line of air conditioning units, which are known for their efficiency and reliability. If you need more specific details about its features or performance, you may want to consult the manufacturer's specifications.


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