IF USING A COPPER AT 105 DEG. CELSIUS - 70 FT. ONE-WAY LENGTH: TO GET AT VOLTAGE DROP = 3.72% AT 25 AMP LOAD ---- USE #1 AWG TO GET AT VOLTAGE DROP = 2.94% AT 25 AMP LOAD ---- USE #1/0 AWG TO GET AT VOLTAGE DROP = 1.85% AT 25 AMP LOAD ---- USE #3/0 AWG
The voltage drop should not exceed 3% on a feeder or branch circuit.
to measure voltage in the circuit
You usually use V for volts. There can also be a subscript. Say for the voltage drop of a resistor could be called VR.
You place the volt meter in parallel with the parallel circuit.
Not enough information. To answer this question the amount of current in AMPS the circuit is drawing is needed.
The voltage drop should not exceed 3% on a feeder or branch circuit.
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
Must also know current load to determine.
to measure voltage in the circuit
This is a voltage drop question. A #2/0 copper conductor will limit the voltage drop to 3% or less. This calculation is for supplying 20 amps over 700 feet using a 110 volt system.
A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 350 amps for 150 feet on a 208 volt system.
You usually use V for volts. There can also be a subscript. Say for the voltage drop of a resistor could be called VR.
It depends on the use it is being put to. It is sufficient for a 24 volt circuit. Too much for a 12 volt circuit and too little for a 240 volt circuit.
Volt difference causes a short circuit! ChaCha
You place the volt meter in parallel with the parallel circuit.
Yes, the voltage listed on the bulb is the nominal voltage and it will work perfectly on a 120 volt circuit.
A volt meter is used to detect the presence of voltage, and it also measure the amount of voltage (electrical pressure) in a circuit.