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47.18 Amps.

Another Answer

The equation for the total power of a balanced three-phase load is:

P = 1.732 x VL IL x power factor, where the subscript, L, represents line values.

So if we change the subject of the equation, for the line current, we have:

IL = P / (1.732 x VL x power factor)

IL = 32 000 / (1.732 x 440 x 0.89)

IL = 47.18 A

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