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What is the typical bandwidth of a channel for a cable modem?

6 MHz


Suggest a possible communication channel for transmission of a message signal of bandwidth of 5 MHz?

sky waves


How much minimum bandwidth is required for multiplexed channel?

The minimum bandwidth required for a multiplexed channel depends on the number of channels being multiplexed and the bandwidth of each individual channel. In general, the total minimum bandwidth needed is the sum of the bandwidths of all the channels being combined. For example, if you are multiplexing four channels, each requiring 1 MHz, a minimum bandwidth of 4 MHz would be necessary. Additionally, some multiplexing techniques may require guard bands to prevent interference, which would increase the total bandwidth requirement.


What is the bandwidth of FM?

88 MHz-108MHz


What is the bandwidth of tv signal?

6 mhz.


What are two speeds of RIMM?

he rating for RIMM memory is based on the maximum theoretical bandwidth (in MHz) and included speed ratings of 800 MHz, 1066 MHz, 1200 MHz, 1333 MHz, and 1600 MHz.


What is the bandwidth of a signal that ranges from 50 KHZ to 2 Mhz?

1.95 MHz 1,950 KHz 1,950,000 Hz


What is the bandwidth of a signal that ranges from 40KHz to 4 MHz?

Solution Let fh is the highest frequency and fl is the lowest frequency. Bandwidth = fh - fl = 4000 - 40 KHz = 3960 KHz = 3.96 MHz


What Is an 802.11n feature that allows two adjacent 20-MHz channels to be combined to make a 40-MHz channel?

Channel bonding


Is an 802.11n feature that allows two adjacent 20-MHz channels to be combined to make a 40-MHz channel?

Channel bonding


How wide is each channel on an 802.11b-compliant DSSS system?

22 MHz Each channel is a contiguous band of frequencies 22 MHz wide


What is the required bandwidth of a low pass channel to transmit 1mbps by baseband communication?

The answer depends on the accuracy desired. a. The minimum bandwidth, a rough approximation, is B = bit rate /2, or 500 kHz. We need a low-pass channel with frequencies between 0 and 500 kHz. b. A better result can be achieved by using the first and the third harmonics with the required bandwidth B = 3 × 500 kHz = 1.5 MHz. c. A still better result can be achieved by using the first, third, and fifth harmonics with B = 5 × 500 kHz = 2.5 MHz