You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)Note: If you try this at home, be aware that these resistors will dissipatethe 5 ohm . . . 58.8 wattsthe 10 ohm . . . 117.6 wattsthe 20 ohm . . . 235 watts .These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ
maybe 10 amperes
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
Yes, a 10 amp AGC fuse can be used in a 10 amp rated DC circuit as long as the fuse rating matches the circuit's ampacity. This ensures that the fuse will blow before the circuit is overloaded, protecting the circuit from damage and potential hazards.
A 20-amp circuit can typically support up to 10 receptacles.
No, # 10 wire is only rated at 30 amp maximum.
A 20 amp circuit with #12 gauge wire will work in any event but if the nameplate recommends a 15 amp circuit then #14 gauge wire on a 15 amp circuit is sufficient. In either case you will have a double pole breaker and your equipment may not require a neutral. Always run a grounding conductor.
Resistance is Volts over Current 11 Ohm = 110Volt / 10 Amp
The recommended wire size for a 30 amp circuit is typically 10 gauge wire.
The recommended wire size for a 30 amp circuit is typically 10 gauge wire.
For a 25 amp circuit, the appropriate wire size is typically 10 gauge wire.
The appropriate wire size for a 30 amp circuit is typically 10 gauge wire.