If the motor is a three phase the most likely voltage the motor operates on will be 480 volts.
Motors are rated either in Watts or Amps, and by Voltage. If the motor is rated in Amps, that is the fuse or circuit breaker size you will need. If rated in Watts, you will have to use the formula P=IE, where P is power in Watts, I is current in Amps, and E is Electromotive Force in Volts. Since we know the watts and volts, we solve for current, thus: I=P/E, and I will be your current rating. One note: These calculations give the MINIMUM rating needed for the motor to run. Fuses and circuit breakers are usually designed so that they will break if the circuit pulls 250% of the Motor's rating.
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
voltage would go up typically (you would raise the voltage, not the fan circuit), but it depends on the motor
No, not directly. The supply voltage has to rise or the resistance has to fall to get over-current. If there was a secondary control voltage that was part of a voltage control circuit for a higher voltage, it is conceivable that a voltage drop in control circuit could cause an over-voltage in the supply. Motors are constant power devices, so this could be true for a motor. If you have a 1hp motor (loaded at 1hp), it will want to draw 1hp of power no matter the supply voltage. If the voltage dips, the motor will require more current to keep it spinning at it's normal speed.
The voltage drop should not exceed 3% on a feeder or branch circuit.
Cannot answer this question. Will need to know the voltage and amperage of the circuit. Also need to know the application i.e. is it a lighting circuit or a motor circuit?
LT motors are those motor whose voltage rating is less than 415v.
The circuit breaker is sized to the full load amps of the motor times 250%.
These types of motors are classified as dual voltage motors. The highest motor voltage rating is always double the lowest voltage rating. Dual voltage motors are more versatile in matching the system voltage supply that they are connected to. When the motor uses the highest voltage rating the coil legs are in series, dropping the high voltage across two coils. When the motor is connected to the low voltage rating the coils are connected in parallel dropping the low voltage rating across the two coils in parallel. As you can see no matter which configuration that you use the individual coils can never get a voltage across them greater than the lowest of the two voltages available. The connection diagram is usually on the underside of the motor's junction box lid.
Motors are rated either in Watts or Amps, and by Voltage. If the motor is rated in Amps, that is the fuse or circuit breaker size you will need. If rated in Watts, you will have to use the formula P=IE, where P is power in Watts, I is current in Amps, and E is Electromotive Force in Volts. Since we know the watts and volts, we solve for current, thus: I=P/E, and I will be your current rating. One note: These calculations give the MINIMUM rating needed for the motor to run. Fuses and circuit breakers are usually designed so that they will break if the circuit pulls 250% of the Motor's rating.
First of all, what voltage are you going to use and second, what is the horsepower of the motor?
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
voltage would go up typically (you would raise the voltage, not the fan circuit), but it depends on the motor
There are a number of devices that break a circuit. On motor circuits an overload block opens the circuit when the motor's current goes above the motor's nameplate rating. Likewise a fuse or a breaker will open a circuit when the current goes above their rated limit. In home wiring circuits the home devices are controlled by a simple on- off switch. Electric heating circuits are controlled by thermostats that regulate the heaters by opening and closing the heater's supply voltage.
It is not recommended to power a 480 volt motor with a 575 volt drive as the drive output voltage may exceed the motor's insulation rating, potentially causing damage to the motor. It is best to use a drive that matches the motor's voltage rating to ensure safe and efficient operation.
A contactor is another name for an electrical relay. It is a device that allows a low current (normal) switch to turn on or off high current equipment such as heaters or air-conditioners that would be well beyond its capacity.
No, not directly. The supply voltage has to rise or the resistance has to fall to get over-current. If there was a secondary control voltage that was part of a voltage control circuit for a higher voltage, it is conceivable that a voltage drop in control circuit could cause an over-voltage in the supply. Motors are constant power devices, so this could be true for a motor. If you have a 1hp motor (loaded at 1hp), it will want to draw 1hp of power no matter the supply voltage. If the voltage dips, the motor will require more current to keep it spinning at it's normal speed.