That depends on actual circuit impedances and without knowing them cannot be answered in any way. But if all the circuit impedances are purely resistive, there will be no change in current flow with any change in frequency.
When the frequency of Parallel RL Circuit Increases,XL increases which causes IL (current through inductor) decreases. Decrease in IL causes It (It=Il+Ir) to decrease,which means by relation IT=Vs/Zt ,the Zt (Total Impedance) Increases.
A: the gain will be maximum at the open loop configuration and decrease as frequency increases
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
When the frequency of Parallel RL Circuit Increases,XL increases which causes IL (current through inductor) decreases. Decrease in IL causes It (It=Il+Ir) to decrease,which means by relation IT=Vs/Zt ,the Zt (Total Impedance) Increases.
Capacitive reactance (expressed in ohms) is inversely-proportional to the supply frequency, so it will decrease when the frequency increases. The following equation applies:XC = 1/(2 pi f C)where:XC = capacitive reactance, in ohmsf = frequency, in hertzC = capacitance, in farads
Increase decrease. The frequency MUST decrease.
If you're talking about an electric motor, increasing the frequency will increase the speed of rotation of the motor, and decreasing the frequency will decrease the speed of rotation of the motor. The other way of controlling a motor is to control the current; increasing the current increases speed, decreasing current decreases speed.
period
Pressure has a direct relationship with the speed of sound, which in turn affects the frequency of a wave. As pressure increases, the speed of sound increases. This causes the wavelength to decrease, resulting in an increase in frequency. Conversely, a decrease in pressure would lead to a decrease in frequency.
when the frequency is increased the total impedance of a series RC circuit is decrease.
Dear Friend, we can observe over speed when frequency is increase in alternating current ANSWER: You will see that the time between peaks will shorten up. If rectified the amount of capacitance to reduce ripple will decrease.
when the current increases in voltages.
If the period increases, the frequency decreases.The product of (frequency) times (period) is always ' 1 '.
The maximum value of the current in an AC circuit depends on the frequency of the voltage source. As the frequency increases, the maximum current value also increases.
Wave frequency decreases when the wavelength of the wave increases. This means that less waves pass through a point in a given time, resulting in a decrease in frequency.