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What was the effect on the input impedance of lowering the operating frequency?
The input impedance should increase slightly for the lower frequency, when using a capacitive circuit.
When the frequency of the voltage applied to a series RC circuit is increased the total impedance?
When the frequency of the voltage applied to a series RC circuit is increased, the total impedance decreases. This is because the reactance of the capacitor (Xc = 1/(2πfC)) decreases with increasing frequency, leading to a lower overall impedance. As a result, the circuit allows more current to flow. The resistive component remains constant while the capacitive reactance diminishes, causing the total impedance to drop.
At a frequency below the resonant frequency parallel circuit is?
A parallel resonant circuit has low impedance, when non resonant; however the impedance rises sharply, as the circuit comes to resonance.
Why the current increases upto resenance frequency and decreases there after in a series LCR circuit?
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
In an AC circuit with only an inductor what will an increase in frequency do?
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
What happens to the total impedance of a series RC ciRCuit as the frequency is increased?
when the frequency is increased the total impedance of a series RC circuit is decrease.
What was the effect on the input impedance of lowering the operating frequency?
The input impedance should increase slightly for the lower frequency, when using a capacitive circuit.
When the frequency of the voltage applied to a series RC circuit is increased the total impedance?
When the frequency of the voltage applied to a series RC circuit is increased, the total impedance decreases. This is because the reactance of the capacitor (Xc = 1/(2πfC)) decreases with increasing frequency, leading to a lower overall impedance. As a result, the circuit allows more current to flow. The resistive component remains constant while the capacitive reactance diminishes, causing the total impedance to drop.
At a frequency below the resonant frequency parallel circuit is?
A parallel resonant circuit has low impedance, when non resonant; however the impedance rises sharply, as the circuit comes to resonance.
Why the current increases upto resenance frequency and decreases there after in a series LCR circuit?
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
In an AC circuit with only an inductor what will an increase in frequency do?
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
Why LC parallel resonance circuit has maximum impedance?
An LC parallel resonance circuit exhibits maximum impedance because at the resonance frequency, the inductive and capacitive reactances cancel each other out. This occurs when the frequency of the input signal matches the natural frequency of the circuit, leading to a condition where the total impedance is dominated by the resistive components. As a result, the circuit presents a high impedance to the source, minimizing current flow. This characteristic is fundamental in applications such as tuning and filtering in electronic circuits.
Does resonant frequency of RLC series circuit depends on Resistance?
No, the resonant frequency of a RLC series circuit is only dependant on L and C. R will be the impedance of the circuit at resonance.
How does an RLC circuit affect amplitude?
An RLC circuit can affect the amplitude of a signal by either amplifying or dampening it. The circuit can resonate at a specific frequency, causing the amplitude of the signal to increase (in resonance) or decrease (out of resonance) depending on the values of the components. The circuit's impedance at a given frequency dictates how much the signal's amplitude will be affected.
Does a lower impedance increases or decreases the short circuit amps available at the terminals of transformers?
Increases
What is dynamic impedance?
The impedance of a circuit having an inductance and a capacitance in parallel at the frequency at which this impedance has a maximum value. Also known as rejector impedance.
What is the effect of transformer impedance on short circuit current?
Short circuit current will increase a lot.
