A squirrel-cage rotor consists of uninsulated copper or alumnium bars, short-circuited by rings located at opposite ends, and semi-enclosed within a laminated iron rotor, and there is no provision for any form of external connection. So it would be quite impractical to do what you suggest.
unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance
An electron traveling through the wires and loads of the external circuit encounters resistance.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
If measuring resistance of materials or resistors by themselves(not soldered into a circuit board) resistance is constant. If measuring resistance of a circuit then it could fluctuate with the components functioning in the circuit.
On Circuit Resistance = Close to the total load Resistance. Off Circuit Resistance = Near Infinitive High Resistance.
A squirrel-cage rotor consists of uninsulated copper or alumnium bars, short-circuited by rings located at opposite ends, and semi-enclosed within a laminated iron rotor, and there is no provision for any form of external connection. So it would be quite impractical to do what you suggest.
To limit the starting current in slip ring induction motors.
R=1/(1/ R1 +1/ R2 +1/ R3 +.........) Where R is the total external resistance(effective resistance) in an electric circuit.
R=1/(1/ R1 +1/ R2 +1/ R3 +.........) Where R is the total external resistance(effective resistance) in an electric circuit.
External voltage is the ration when there is an increase in current and voltage. If you apply voltage to the outside of a circuit and need to figure out the amount of current flow, that would be the external resistance.
unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance
An electron traveling through the wires and loads of the external circuit encounters resistance.
If Rin = Rout, then the voltage at the output of the device goes down to half of the value that the circuit has without the external resistance. Scroll down to related links and look at "Interconnection of two audio units".
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
No. There should be substantial resistance only where the circuit design needs it and wants it, and as little as possible everywhere else in the circuit.
Any specific device that draws a current which is connected within the circuit is an example of a circuit load. That may be a resistance and a loudspeaker LED computer and induction motor or whatever which can withdraw the energy from the output.
The voltmeter has an internal resistance, which should be as high as possible. As this resistance draws current from the circuit under test, it will affect circuit operation. This is more pronounced in a high impedance circuit because the current drawn flows through higher resistances.