Hemolysis typically occurs in red blood cells when they are exposed to a NaCl concentration below approximately 0.45% (or 0.15 M). At this concentration, the osmotic pressure causes water to enter the cells, leading to swelling and eventual rupture. Conversely, NaCl concentrations above this level are generally isotonic or hypertonic, preventing hemolysis.
2% NaCl is hypertonic to red blood cells causing them to shrink and crenate due to water moving out of the cells by osmosis. Hemolysis is likely to occur in hypotonic solutions where red blood cells swell and burst.
This should be compared to something before determination can be done. For ex. if relative to blood, 2.8 % of Nacl will cause crenation since it's more hepertonic than blood. Liquid/solute in the blood will then difuse to go out (fr its low concentration) of the RBC cell to a higher concentration wich is Nacl.
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
LIVER
The concentration of NaCl in a solution that contains 0.9 NaCl is 0.9 grams of NaCl per 100 grams of solution.
If you expose red blood cells to a high concentration of NaCl (salt), water will move out of the cells through osmosis, causing them to shrink and potentially undergo hemolysis (bursting). This process is known as crenation.
The electrical conductivity of the solution will be higher if the concentration of NaCl increase.
The freezing point of the solution depends on the NaCl concentration.
Increase the concentration of NaCl evaporating the water.
Sheep blood
the concentration of Cl- increase (common ion), but the pH of the solution remain same.
hypotonic solution