Approx. 14 g/L
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
To find how much salt can be obtained, we need to calculate the mass of NaCl in 274 g of seawater. Since the concentration of NaCl in seawater is 3.5 g per 100 g of water, the mass of NaCl in 274 g of seawater is 9.59 g. Therefore, 9.59 g of salt can be obtained from 274 g of seawater.
The molarity is 6.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).
To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.
The most important salt in seawater is sodium chloride, NaCl.
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
I suppose that this situation is not possible.