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What else can I help you with?
What is needed to calculate the voltage across a device?
you calculate a voltage circuit by taking it apart and findng the circuit and calculate the voltage and then resible it.
If a circuit has a voltage drop of 60.0 V across a 120.0 resistor that carries a current of 0.500 A. What is the power conducted by the resistor Use P VI.?
Well, if the question says "use P = VI", just do it! You have the values of voltage (V) and current (I) right there.
Why is series resistor in all bias experiment?
biasing resistor is important because the voltage passing through it will limit the current and derive the next device, i.e. transistor etc. when a signal is applied to this circuit, biasing resistor helps to signify that signal and as a result we can examine our output.
What is the current running through resistor 1?
I'm having some trouble focusing in on the schematic of the circuit.
What is the voltage between c and d?
I think the question probably needs a diagram with it. In general, the method to determine the voltage is to add up (sum) the voltages as you go around the circuit. Your battery or source will add volts. Most of the other devices will subtract volts. The total will be zero, or in other words, the things that add volts will equal the things that subtract volts. For example, if you have a series circuit where there is only one path, if the battery adds 12 volts and the first resistor takes away 7 volts, there will be 5 volts across the second resistor. Something to note, though, involves parallel circuits. When the circuit splits into two paths, the voltage measured between the place they split and the place they rejoin is the same.
What work resistor?
when a resistor is connected in a circuit it drop some voltage across it.when a circuit have large input voltage then by using a resistor of suitable value we get the desired voltage.
Does a resistor reduce current or voltage in an electrical circuit?
A resistor reduces the flow of current in an electrical circuit, which in turn affects the voltage across the resistor.
What is the mathematical relationship between heat dissipation and applied voltage?
Heat dissipation is directly proportional to the square of the applied voltage according to Joule's Law. This means that as the voltage increases, the heat dissipated in a circuit also increases quadratically. The relationship is represented by the formula: Heat dissipation = V^2/R, where V is the voltage and R is the resistance in the circuit.
What parts of a circuit acts as a resistor?
Any part of a circuit that has a voltage drop across it is a resistor.
What is the rule for voltage across each resistor?
The rule for voltage across each resistor in a series circuit is that the total voltage supplied by the source is equal to the sum of the voltage drops across each resistor. In a parallel circuit, the voltage across each resistor is the same and equal to the source voltage.
How does ohm's law works in a resistor circuit?
Ohm's law states that voltage is resistance times current. In a resistor circuit, knowing two of voltage, current, or resistance, you can calculate the third.Actually, this applies to any circuit, be it resistor, capacitor, or inductor. Ohm's law still applies - it just gets more complex when the phase angle of current is not the same as the phase angle of voltage.
How do you calculate the ir1 and ir2 in a parallel circuit?
To calculate the currents ir1 and ir2 in a parallel circuit of two resistors r1 and r2, consider the voltage across them. By Kirchoff's voltage law, the voltage across each resistor will be the same, so simply use Ohm's law to divide voltage by each resistor to get each resistor's current. ir1 = v / r1 ir2 = v / r2 If you don't know voltage, but you do know total current, then determine the total resistance as RT = R1R2/(R1+R2), calculate voltage as ITRT and proceed from there.
How resistor are tested given a voltage source and ammeter?
I can think of the following characterisatics of a physical resistor that would beimportant to know in various circuit design situations:ResistancePower dissipation capabilityEquivalent parallel capacitanceEquivalent series inductanceI think it's accurate to say that Resistance is the only one that can be measuredwith a voltage source and ammeter.It would be necessary to know the voltage of the voltage source. Then proceedas follows:Connect the voltage source, resistor, and ammeter in series.Energize the voltage source.Read the ammeter.The resistor's resistance is (Voltage)/(Current, as indicated by the ammeter).
Is the heat loss and current of a resistor affected by being in a parallel circuit or can you just calculate it the same as in series?
The heat generated by any particular resistor depends (at least electrically) solely on the power it dissipates. Power dissipation in a resistor is equal to current squared times resistance, and the current through the resistor is equal to the voltage across it divided by the resistance. If we take a 10 ohm resistor ('your resistor') and put it in a series circuit such that there is 10 volts across your resistor, the current through it will be 1 ampere (10/10=1). the power dissipated will be 10 watts (1^2 * 10=10). If we put your resistor in a parallel circuit that also puts 10 volts across it, then the current and power will be the same. Your resistor does not know or care where the voltage came from. From this point of view, once you get down to the voltage across the resistor, it does not matter what type of circuit it is in. On the other hand, for any given power supply voltage, then the type of circuit and the value of external components certainly does affect the terminal voltage and thus the current through as well as the power dissipated by the resistor. In a parallel circuit, the voltage across your resistor remains basically the same no matter what resistance you put in parallel with it (unless you overload the power supply or the power supply has high internal resistance). In this case, the voltage across the resistor is the same as the power supply, current is I=E/R, R being that resistor only, and power is P=I^2 * R. In a series circuit the current through the resistors is I=E/R, R being the total resistance (including the other resistor(s)). The power dissipation in your resistor will then be P=I^2 * R, I being the series current we just calculated, and R being your resistor only. Since the other resistors affect the current, and since the current is the same no matter where you measure in a series circuit, then the voltage across your resistor and thus the power dissipation will be affected. The voltage across your resistor will be E=I*R, I being the series current we just calculated, and R being your resistor only. So, while the calculation for power dissipated in a particular resistor does not change relative to what type of circuit it is in, the calculation to arrive at the voltage across the resistor and/or the current through it (which you will then need to calculate power) does. Keep in mind there are other mechanical parameters that influence the actual case temperature of the resistor. Physical size of the case, composition, and airflow velocity, if any, will alter the case-to-ambient thermal conductivity. Ambient temperature will also be a factor in the final temperature.
How does a resistor limit current or voltage in an electrical circuit?
A resistor limits current in an electrical circuit by impeding the flow of electrons, which reduces the amount of current passing through it. This, in turn, helps regulate the voltage in the circuit by creating a drop in voltage across the resistor.
How does a resistor reduce voltage in an electrical circuit?
A resistor reduces voltage in an electrical circuit by converting some of the electrical energy into heat. This process slows down the flow of electricity, resulting in a decrease in voltage across the resistor.
How does a resistor affect the flow of electricity in a circuit: does a resistor reduce voltage or current?
A resistor affects the flow of electricity in a circuit by reducing the current that flows through it. This reduction in current leads to a decrease in voltage across the resistor.
