Theoretically not allowed and practically not safe or desirable to have two current sources in series or two voltage sources in parallel. In practice, the sources will get hot and catch on fire -- very unwise to even try.
If there are only a resistor and a capacitor in the circuit, then the phase shift will indeed be between 0 and 90 degrees. When the resistor and capacitor are in series, the phase shift will be negative when the capacitor is connected to a source voltage and the resistor is the load. The phase shift will be positive when the resistor is connected to the source. The lower the values of R and C, the higher the frequency bandwidth.With the resistor and capacitor connected in series and the two parts connected to a current source, the phase shift will be negative. At high frequencies, the output voltages is lower, and the circuit appears as a very low impedance. At low frequencies, the circuit looks more like a resistor. Again, the phase shift will be between 0 and 90 degrees.CommentThe correct term is phase angle, not 'phase shift'. By definition, the phase angle is the angle by which the load current leads or lags the supply voltage. For an RC circuit, the current leads the voltage, so the phase angle is a leading phase angle.
If you are saying that the Zeners are connected in series, the answer is Yes.
The current in each resistor in a series circuit is the same. Kirchoff's Current Law states that the sum of the currents entering a node must add up to zero. The connection between two resistors in a series circuit is a node. The current entering the node from one resistor is equal to the current leaving the node into the next resistor.
Brighter in parallel. In series the voltage is divided between the two bulbs, thus the current will only be half so that the power of each bulb will only be one quarter (of 5 watts) in the series set-up.
The wattmeter contains two coils one is current coil and other is pressure coil.the current coil is connected in series with the line and pressure coil is connected across the supply.so, the disc links with the flux which is the resultant of these two.(resultant means consider the vector resultant), which include phase angle also.the active power P=VI(cosine of angle between v & I).there fore the wattmeter measures the active power.CommentThere is no 'disc' in a wattmeter. Furthermore, the current coil doesn't measure the load current, it measures the in-phase component of the load current.
Because the total current is divided between the two components. For example, if the current was one amp, and you connected two bulbs in series, ech bulb would get half an amp of current. As brightness is proportional to current, this means they glow more dimly.
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
It is impossible for a series circuit to have two points with two different currents. Kirchoff's Current Law states that the signed sum of the currents entering a node is zero. A consequence of this is that the current in every part of a series circuit is the same. Please restate the question, giving correct information.
Two common ways to wire an electric circuit are in series, where the components are connected one after another in a single pathway for the current to flow through, and in parallel, where the components are connected in separate branches to the power source, allowing the current to flow through multiple paths simultaneously.
The circuit is a series circuit when two objects are connected in a single path. In a series circuit, the current flows through each object in succession.
as the given cells have the same current flowing in through them (current flowing through the cells connected in series is equal to the current flowing when connected in parallel ) equate the formula's of cells connected in series and cells connected in parallel.thus by equating we get the value of the internal resistor as 2 ohms.
If three lamps are connected in parallel and one blows out, the current in the other two does not change. This assumes that the net change in total current does not cause the power source to change voltage.
In a series circuit, there is only one path for current flow, as the components are connected end-to-end. In a parallel circuit, there are multiple paths for current flow, as the components are connected side-by-side, allowing current to travel through each branch independently.
Current will always flow in both resistors, but the one with the lower resistance will have more current flow through it. The value of the current in each resistor is calculated by dividing the voltage of the source by the resistance of the individual resistor. As long as the capability of the power source isn't exceeded, the current through each resistor isn't affected by the presence of the other resistor. Said another way, if two resistors are connected in parallel across a source, neither one "cares" that the other resistor is connected across the source. The two resistors work independently.
Take the internal series resistance of the voltage source and make it the internal parallel resistance of the current source. Then compute using Ohm's law the current of the current source to be equal to the maximum current the original voltage source could supply a short circuit load. Note: the two sources are equivalent.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
When battery cells are connected in series and a conducting circuit is connected between the terminals of the string, the current out of the positive terminal of each cell and the current into the negative terminal of each cell are all the same number.