pH + pOH = 14
i dont know i need help with this question as well
If a strong acid is mixed with a weak base, pH=pKa+/-1 in the buffer region.Corrected:If a strong base is mixed with a weak acid pOH= pKb +/-1 ( pH=(14 - pKb)+/-1) in the buffer region[Remember: For one conjugated pair of weak acid (a = HB) AND its weak base (b = B-):pKa + pKb = 14.0andpH + pOH = 14.0
Distinguish between a public law relationship and a private law relationship.
What is the relationship between ethics and WHAT? You need at least two things to have a relationship.
a relationship between brothers should be sacred and good....
To find the pOH of a solution, you can use the relationship between pH and pOH, which is given by the equation: pH + pOH = 14. If the pH of the solution is 6.2, then the pOH can be calculated as follows: pOH = 14 - pH = 14 - 6.2 = 7.8. Therefore, the pOH of the solution is 7.8.
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
pH + pOH =14
The concentration of hydroxide ions (OH-) in a solution with a pH of 4.0 is 1 x 10^-10 mol/L. This value can be calculated using the relationship between pH and pOH (pOH = 14 - pH), and then using the formula for the concentration of hydroxide ions in water at a given pOH.
The pOH is 6,4.
The pOH is 6,4.
10.7(pH) - 14 = 3.3 (pOH)
1.8
It will have a pOH of 12. Because pH+pOH=14
The pOH of ammonia is approximately 4.7. Ammonia, NH3, is a weak base with a Kb value of approximately 1.8 x 10^-5. To find the pOH, you would first find the pH of the solution using the equilibrium constant for the base dissociation reaction and then use the relationship pOH = 14 - pH.