Sure. It is just a DC to AC power inverter. Just Google DC AC Inverter or Power Inverter. The most common variety is 12 VDC to 120 VAC because of automobiles. You'll have to match your power requirements with various models. 120 VDC doesn't seem to be a common supply voltage.
You can change from one voltage to another using a appropriate converter. For AC, you need a transformer. For DC, you need a DC-DC converter, which are complex little devices. There is no fixed values to change from one voltage to another. You can change from any voltage to any voltage with the right hardware and circuit design. Keep in mind, the more esoteric the change, the more expensive it will become as you drift from off-the-shelf solutions. 200V is an odd voltage. US Residential service has 240VAC for large appliances. That may be what you are looking for. There are many entries on this site about how to add a 240VAC outlet.
You have to use a step down transformer.
12 watts
I imagine it depends where you live... 120v in USA, and 230v in UK & spain.
No. Some carry batteries internally (handhelds), and some are wired for 120v power (base stations).
A 120V household electrical outlet supplies 12 watts of powerwhen the current is 0.1 Ampere (and the power factor is 100%).
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For the same power - Watts - you need to run twice as many amps at 220V than at 440V. For the same load, it'll pull half the amps at 220V than it did on 440V
35mfd/440V
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V side to the neon sign and you should have light. Transformer should be at least 100va. This will give you an output of .83 amps at 120V
All three, on 110V a split receptacle, on 220V a baseboard heater, on 440V a construction heater or similar resistive load.
Just calculate from motorplate: Watts/(Square3*V*cosP)=> example motorplate says: 4.7Kw 440V cosP: 0.82 4700W/(square3*440V*0.82) here you get minimum setting for motor, this case 7.5A JT
Depends on the motor. If it is a synchronous motor it will run too fast.
If you live in a country where your supply is (as in Argentina 220/440v) then this is the carrier voltage.
Please go to discuss question page.
120v
First of all, what voltage are you going to use and second, what is the horsepower of the motor?
The three generated waves in three phase are spaced 120 degrees apart.