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Polonium-210 become lead-206 after the emission of an alpha particle.

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10y ago

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Why does the polonium (po) become lead (pb) after a decay?

Polonium-210 lose an alpha particle and become lead-206.


What does polonium change into?

Polonium-210 decay to lead-206.


What does bismuth 210 become when it undergoes alpha decay?

bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206


What is alpha decay of polonium 210?

The reaction is:Po-210------------alpha particle------------------Pb-206


What equation correctly represents alpha decay of polonium 214?

The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.


What element does an atom of polonium change into after it emits an alpha particle?

Polonium 210-----------alpha particles-----------Lead 206 Polonium 209-----------alpha particles-----------Lead 205 Polonium 208-----------alpha particles-----------Lead 204 Polonium 214-----------alpha particles-----------Lead 210 Polonium 218-----------alpha particles-----------Lead 214 (99,98 %) Polonium 218-----------beta particles------------Astatin 218 (o,o2 %) For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes


Lead-210 and lead-206 are different of lead?

isotopes


What kind of particle is released when Po-210 becomes Pb-206?

alpha particle dont ask why cuz i dont know


What is the radiation of polonium 210?

Polonium-210 is an alpha emitter.


What are the two radionuclides which concentrate on seafood?

Although Mercury can be found in fish and shellfish the two radionuclides which concentrate in seafood are Lead-210 and Polonium-210. (Source: FEMA Radiological Emergency Management Course IS-3)


What If there are 128 neutrons in Pb 210 how many neutrons are found in the nucleus of Pb 206?

Lead-210 has 82 protons, so 128 - 82 = 46 neutrons in Pb-210. Lead-206 has 82 protons, so since it's a different isotope, the number of neutrons will differ. Lead-206 has 206 - 82 = 124 neutrons.


How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?

If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).