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1000kg car travelling 25miles per second east has a collision with a 1500 kg van initially at rest using conservation of linear momentum what is their common velocity immediately after the collision? I also assume the 1000 kg car is going 25 m/s, since 25 mi/s = 25 mi/sec * 5280 ft/mi ÷ 3.28ft/m = 40,243.9 m/s or 90,000 mi/hr.(jet speed)

Be careful when you type in units!!

Because the question asks, "what is their "common" velocity immediately after the collision?", I assume they are stuck together. Momentum = Mass * velocity

Think about a heavy object sitting still. Could you move this heavy object by throwing a light object at the heavy object, very fast? Is it possible? That is the theory behind momentum.

Momentum is conserved, so the total momentum of both objects before collision = the total momentum of both objects after collision.

Ma* Va (initial) + Mb*Vb (initial) = (Ma + Mb) * Vtotal(final)

Ma = 1000 kg

Va (initial) = 25 m/s

Mb = 1500 kg

Vb (initial) = 0 (at rest)

(Ma+ Mb) 2500 kg

Vtotal(final) = ?

Substitute the values of the variables into the equation and solve for

Ma* Va (initial) + Mb*Vb (initial) = (Ma + Mb) * Vtotal(final)

(1000 kg) * (25 m/s) + (1500 kg) * ( 0 m/s) = (2500 kg) * Vtotal(final)

Vtotal(final) = (37,500 Kg*m/s ) ÷ (2500 kg)

Vtotal(final) = answer is between 10 m/s and 20 m/s.

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