Basically you need to do an integration, multiplying each mass point by its x-coordinate. Finally you divide by the total mass. Similarly for the y-coordinate.
It is a simple ratio charge/mass or e/m .
scxv cx
Yes, a body in circular motion does have kinetic energy. This kinetic energy is known as rotational kinetic energy and depends on factors such as the mass of the object, its radius of rotation, and its angular velocity.
its where the medians all meet, ie if you draw a line from each vertx to the midpoint of the opposite side where they all meet is the centre of mass its where the medians all meet, ie if you draw a line from each vertx to the midpoint of the opposite side where they all meet is the centre of mass
Momentum is the product of the mass and the velocity of an object. It's SI unit is kgms-1. Correct, but perhaps more easily interpreted as kgm/s.
No, it may lie outside the body. In case of a circular ring, it is at the centre of the ring which is outside the mass of the ring.
Its similar in shape, both are more or less disc shaped. Both have a large mass at the centre. Both have smaller bodies orbiting this mass.
To find the center of mass of a solid hemisphere, you can divide it into elementary components, such as disks or cylindrical shells, and integrate their individual masses over the hemisphere's volume. By dividing the mass-weighted points by the total mass, you can determine the coordinates of the center of mass in three dimensions.
Brandon throws a flying disc with a force of 8 N. If the disc has an acceleration of 4 m/s2, what is the mass of the disc?
It is a simple ratio charge/mass or e/m .
Moment of inertia depends upon the distribution of mass with respect to the axis of rotation.The greater the distance between the bulk of an object's mass and the axis of rotation, the greater the moment of inertia will be. A solid disk has its mass distributed evenly across its diameter, while a ring has its mass concentrated furthest from the centre of rotation.
The tension in the string provides the centripetal force for the mass in uniform circular motion in this experiment. This tension acts towards the center of the circular path, keeping the mass moving in a circular motion instead of following a straight line.
At the centre of the Earth, or any body for that matter, the mass of the Earth is centralised at the centre, At the centre of the earth there is no weight attributable to the earth's mass. But there is weight (a force) attributable to the sun's mass, neatly balanced out by the speed of the earth in its circular orbit. So the weight is mv2/r instead of mg (m= a mass placed at the centre, v=velocity in orbit, r= distance to sun). If the earth slowed to a stop, it, and everything at its centre would accelerate towards the sun. If somehow you could nail the earth down so it didn't fall in, that weight would be measureable with a spring balance. Ignoring galactic and intergalactic forces. I guess that's sophistry really.
At the centre of the Earth, or any body for that matter, the mass of the Earth is centralised at the centre, At the centre of the earth there is no weight attributable to the earth's mass. But there is weight (a force) attributable to the sun's mass, neatly balanced out by the speed of the earth in its circular orbit. So the weight is mv2/r instead of mg (m= a mass placed at the centre, v=velocity in orbit, r= distance to sun). If the earth slowed to a stop, it, and everything at its centre would accelerate towards the sun. If somehow you could nail the earth down so it didn't fall in, that weight would be measureable with a spring balance. Ignoring galactic and intergalactic forces. I guess that's sophistry really.
An apoapsis is the point of a body's elliptical orbit around the system's centre of mass where the distance between the body and the centre of mass is at its maximum.
Centre of mass. It is where the mass appears to act.
At its centre.