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What else can I help you with?
How you can derive mass to charge ratio equation?
It is a simple ratio charge/mass or e/m .
What is the significance of centre of mass of a system?
scxv cx
What is an expression in terms of mass (hanging and revolving) period radius and acceleration of gravity?
The period ( T ) of an object in circular motion, such as a mass hanging from a string and revolving, can be expressed using the formula ( T = 2\pi \sqrt{\frac{r}{g}} ), where ( r ) is the radius of the circular path and ( g ) is the acceleration due to gravity. For a mass ( m ) hanging from a string, the tension in the string provides the necessary centripetal force, which can be analyzed using ( F = m \cdot a ) and relates to the gravitational force acting on the mass. Thus, the relationship between mass, radius, period, and gravity can be synthesized by considering both gravitational and centripetal forces in the context of circular motion.
Does a body in circular motion have kinetic energy?
Yes, a body in circular motion does have kinetic energy. This kinetic energy is known as rotational kinetic energy and depends on factors such as the mass of the object, its radius of rotation, and its angular velocity.
How do you find the center of mass of a triangle?
its where the medians all meet, ie if you draw a line from each vertx to the midpoint of the opposite side where they all meet is the centre of mass its where the medians all meet, ie if you draw a line from each vertx to the midpoint of the opposite side where they all meet is the centre of mass
Is it necessary that centre of mass should always lie inside the body?
No, it may lie outside the body. In case of a circular ring, it is at the centre of the ring which is outside the mass of the ring.
How is the milky way galaxy similar to the solar system?
Its similar in shape, both are more or less disc shaped. Both have a large mass at the centre. Both have smaller bodies orbiting this mass.
How can you find center of mass of solid hemisphere?
To find the center of mass of a solid hemisphere, you can divide it into elementary components, such as disks or cylindrical shells, and integrate their individual masses over the hemisphere's volume. By dividing the mass-weighted points by the total mass, you can determine the coordinates of the center of mass in three dimensions.
Brandon throws a flying disc with a force of 8 N If the disc has an acceleration of 4 ms2 what is the mass of the disc?
Brandon throws a flying disc with a force of 8 N. If the disc has an acceleration of 4 m/s2, what is the mass of the disc?
Why is moment of inertia of a solid disc smaller than that of a ring?
Moment of inertia depends upon the distribution of mass with respect to the axis of rotation.The greater the distance between the bulk of an object's mass and the axis of rotation, the greater the moment of inertia will be. A solid disk has its mass distributed evenly across its diameter, while a ring has its mass concentrated furthest from the centre of rotation.
How you can derive mass to charge ratio equation?
It is a simple ratio charge/mass or e/m .
Why weight of the body is zero at the center of the earth?
At the centre of the Earth, or any body for that matter, the mass of the Earth is centralised at the centre, At the centre of the earth there is no weight attributable to the earth's mass. But there is weight (a force) attributable to the sun's mass, neatly balanced out by the speed of the earth in its circular orbit. So the weight is mv2/r instead of mg (m= a mass placed at the centre, v=velocity in orbit, r= distance to sun). If the earth slowed to a stop, it, and everything at its centre would accelerate towards the sun. If somehow you could nail the earth down so it didn't fall in, that weight would be measureable with a spring balance. Ignoring galactic and intergalactic forces. I guess that's sophistry really.
Why is the weight of a body zero at the center of the earth?
At the centre of the Earth, or any body for that matter, the mass of the Earth is centralised at the centre, At the centre of the earth there is no weight attributable to the earth's mass. But there is weight (a force) attributable to the sun's mass, neatly balanced out by the speed of the earth in its circular orbit. So the weight is mv2/r instead of mg (m= a mass placed at the centre, v=velocity in orbit, r= distance to sun). If the earth slowed to a stop, it, and everything at its centre would accelerate towards the sun. If somehow you could nail the earth down so it didn't fall in, that weight would be measureable with a spring balance. Ignoring galactic and intergalactic forces. I guess that's sophistry really.
What supplies the centripetal force for the mass in uniform circular motion in this experiment?
The tension in the string provides the centripetal force for the mass in uniform circular motion in this experiment. This tension acts towards the center of the circular path, keeping the mass moving in a circular motion instead of following a straight line.
What is an apoapsis?
An apoapsis is the point of a body's elliptical orbit around the system's centre of mass where the distance between the body and the centre of mass is at its maximum.
What decreases the centripetal force?
If a body of mass m is in uniform circular motion with speed v and radius r, then the force acting on it has magnitude F = mv2 / r and is directed towards the centre of the circle. This is termed a "centripetal" (meaning "centre-seeking") force. To decrease the magnitude of the centripetal force, you must therefore either decrease the mass of the body, decrease the orbital speed, or increase the radius of the orbit.
What is the spot where the mass of an object is focused (three words)?
Centre of mass. It is where the mass appears to act.
