yes
To start a stoichiometry problem with only the molarity and volume of a solution, first calculate the number of moles of solute by using the formula: moles = molarity × volume (in liters). Once you have the moles of the solute, you can use the balanced chemical equation to determine the stoichiometric relationships with other reactants or products. This will allow you to convert moles of the solute into moles of other substances involved in the reaction as needed.
735 g of Ca3(PO4)2 are obtained.
To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.
To determine the theoretical yield of aluminum oxide (Al₂O₃), we start with the balanced chemical reaction: 4 Al + 3 O₂ → 2 Al₂O₃. From the stoichiometry, 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Given 1.60 moles of aluminum, we can find the limiting reactant. Since 1.60 moles of Al would require 1.20 moles of O₂ (which is less than the available 1.50 moles), aluminum is the limiting reactant. Thus, 1.60 moles of Al can produce 0.80 moles of Al₂O₃ (from 2 moles Al producing 1 mole Al₂O₃), so the theoretical yield of aluminum oxide is 0.80 moles.
2 moles of Ca and 4 moles of OH
No they are red and gross
well, moles are nocturnal i think so they come up to get some air about 10:00 they start coming out.
Yes of course.. everytime im stressed i get about 10 moles in one time but when everything i good they start fading away!
To start a stoichiometry problem with only the molarity and volume of a solution, first calculate the number of moles of solute by using the formula: moles = molarity × volume (in liters). Once you have the moles of the solute, you can use the balanced chemical equation to determine the stoichiometric relationships with other reactants or products. This will allow you to convert moles of the solute into moles of other substances involved in the reaction as needed.
735 g of Ca3(PO4)2 are obtained.
they both start with the letter m and in science that means they can breed.
You start by checking how many moles of NaCl you have in your pool. Number of moles=concentration*volume =0.048mole/L*455000L=21840moles Then you get the molar mass of NaCl which is 58.443 g/moles, then you multiply it by your number of moles. 21840 moles*58.443g=1'276'395g=1'276.395kg of NaCl
Moles contain twice as much blood and twice as much red haemoglobin as other mammals of similar size, allowing the mole to breathe easily in its underground
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
Umbrellas and uniforms are red. They begin with U.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
this is a easy one. There are only 0.04166 moles.