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Draw and name the enantiomer of D-glucose?
An enantiomer is a pair of structures which are mirror images of each other. For D-glucose:CHO | CHO| | |H--OH | OH--H| | |OH--H | H--OH| | |H--OH | OH--H| | |H--OH | OH--H| | |CH2OH | CH2OHOn the left is D-glucose, and on the right is L-glucose, mirror images.
How do the valence of each element help you determine the structure of the glucose molecule?
The valence of each element in glucose (C6H12O6) is crucial for determining its structure, as it dictates how atoms bond together. Carbon, with a valence of four, can form four covalent bonds, allowing it to create a backbone for the molecule. Oxygen, with a valence of two, can form two bonds, typically linking to carbon and hydrogen. This bonding arrangement results in the ring structure of glucose, where carbon atoms form a cyclic arrangement with hydroxyl (–OH) groups attached, defining its chemical properties and reactivity.
What are the new OH groups formed on each glucose molecule?
Each glucose molecule forms three new hydroxyl (OH) groups upon ring closure in the cyclic form. These OH groups are located at carbon positions 1, 4, and 6 in the glucose molecule, resulting in a hemiacetal structure.
Which form of D-glucose in the ring configuration has the -OH at carbon-1 below the ring in the Haworth Projection?
In the Haworth Projection, the form of D-glucose with the -OH at carbon-1 below the ring is in the alpha-D-glucopyranose form. This form has the -OH group at carbon-1 pointing downwards in the ring structure.
Structure of glucose vs fructose?
The structure of Galactose monosaccharide sugar is a normal chain of six carbon atoms. It is an isomer of Glucose and Fructose. Below is a structure of Galactose in open chain form:H-C=O|H-C-OH|OH-C-H|OH-C-H|H-C-OH|H-C-OH|OHTo understand the pyranose ring form of Galactose, draw a hexagon, assume the joints as carbon atoms except one joint- that is an oxygen atom.Let the joints be A, B, C, D, E, F. To the joints A, C, D, E, F, assume them to be carbon atoms, and the joint B to be oxygen atom. They are joined to each other by single bonds. Now attach -CH2OH group to carbon atom A vertically upwards and -H vertically downwards. Leave oxygen atom B as it is because its stabilised. To carbon atom C, attach -H vertically upwards and -OH group vertically downwards. Repeat this with carbon atom D; & reverse the positions of -H and -OH group in the carbon atoms E and F, as it is done in the open chain form. Actually, in very brief, you only have to show glycosidic-1,4 linkage in the open form of Galactose to express it in pyranose ring form.
Draw and name the enantiomer of D-glucose?
An enantiomer is a pair of structures which are mirror images of each other. For D-glucose:CHO | CHO| | |H--OH | OH--H| | |OH--H | H--OH| | |H--OH | OH--H| | |H--OH | OH--H| | |CH2OH | CH2OHOn the left is D-glucose, and on the right is L-glucose, mirror images.
How do the valence of each element help you determine the structure of the glucose molecule?
The valence of each element in glucose (C6H12O6) is crucial for determining its structure, as it dictates how atoms bond together. Carbon, with a valence of four, can form four covalent bonds, allowing it to create a backbone for the molecule. Oxygen, with a valence of two, can form two bonds, typically linking to carbon and hydrogen. This bonding arrangement results in the ring structure of glucose, where carbon atoms form a cyclic arrangement with hydroxyl (–OH) groups attached, defining its chemical properties and reactivity.
What are the new OH groups formed on each glucose molecule?
Each glucose molecule forms three new hydroxyl (OH) groups upon ring closure in the cyclic form. These OH groups are located at carbon positions 1, 4, and 6 in the glucose molecule, resulting in a hemiacetal structure.
Which form of D-glucose in the ring configuration has the -OH at carbon-1 below the ring in the Haworth Projection?
In the Haworth Projection, the form of D-glucose with the -OH at carbon-1 below the ring is in the alpha-D-glucopyranose form. This form has the -OH group at carbon-1 pointing downwards in the ring structure.
What does a simple sugars chemical structure look like?
The chemical structure of a simple sugar, such as glucose or fructose, is a monosaccharide composed of carbon, hydrogen, and oxygen atoms arranged in a ring structure. For example, glucose has a molecular formula of C6H12O6 and its ring structure consists of a six-carbon chain with hydroxyl (-OH) groups attached to each carbon atom.
Why beta glucose is more stable than alpha?
They form different disaccharides due to there molecular structures. Alpha forms Maltose with a 1-4 glycosidic bond between each alpha glucose and another, and Beta forms the disaccharide Cellobiose with a 1-4 glycosidic bond between each beta glucose and another.
Structure of glucose vs fructose?
The structure of Galactose monosaccharide sugar is a normal chain of six carbon atoms. It is an isomer of Glucose and Fructose. Below is a structure of Galactose in open chain form:H-C=O|H-C-OH|OH-C-H|OH-C-H|H-C-OH|H-C-OH|OHTo understand the pyranose ring form of Galactose, draw a hexagon, assume the joints as carbon atoms except one joint- that is an oxygen atom.Let the joints be A, B, C, D, E, F. To the joints A, C, D, E, F, assume them to be carbon atoms, and the joint B to be oxygen atom. They are joined to each other by single bonds. Now attach -CH2OH group to carbon atom A vertically upwards and -H vertically downwards. Leave oxygen atom B as it is because its stabilised. To carbon atom C, attach -H vertically upwards and -OH group vertically downwards. Repeat this with carbon atom D; & reverse the positions of -H and -OH group in the carbon atoms E and F, as it is done in the open chain form. Actually, in very brief, you only have to show glycosidic-1,4 linkage in the open form of Galactose to express it in pyranose ring form.
What does sugar molecule look like?
Monosaccharides are building blocks of carbohydrates. They can exist in chain form or ring form, and in many cases, the only difference in these structures is in the arrangement of the hydroxyl groups.
Does DNA have a 2' OH group in its structure?
No, DNA does not have a 2' OH group in its structure.
Is glucose soluble?
Glucose is sparingly soluble in ethanol. This is because the organic molecules of the ethanol are too large to separate the glucose, unlike water where the water molecules are easily able to dissolve the crystalline structure to react with the -OH groups.
Why glucose is not soluble in petrol but soluble in water?
glucose molecule contains OH groups, which forms hydrogen bonds with OH of water molecules, therefore glucose is soluble in water. however in patrol is an hydrocarbon compounds, glucose is polar and patrol is non polar (so like dissolves only like), glucose in not soluble in patrol.
Why glucose is less soluble in water?
glucose has less solubility than sodium chloride because of the more OH bonds
