yes Zn + 2HCl -> ZnCl2 + H2 is balanced
When an acid (like hydrochloric) is added to a metal (like zinc, magnesium, etc) bubbles are formed. The gas produced is hydrogen, and a salt is also formed, e.g:2Mg + 2HCl ---> 2MgCl + H2gasMetal + Acid → Salt + Hydrogen gas, e.g. magnesium + sulfuric acid → magnesium sulfate + hydrogen gas. Symbol equation would be Mg + H2SO4 → MgSO4 + H2gasAnother Answer:An acid would react with a metal to produce a salt and hydrogen gas. Examples:Mg + H2SO4 ---> MgSO4 + H2gas --and-- 2Na + 2HCl ---> 2NaCl + H2gasMore Information:Generally, some acids react with some metals but all acids do not react with all metals. However, if there is a reaction, the metal will react with the acid producing the salt of that metal and that acid (as above). Again, generally, the other product of the reaction will be hydrogen gas, although there are some exceptions to this, e.g:Cu + 4(con.)HNO3 = Cu(NO3)2 + 2NO2 gas + 2H2ONO2 is a brown, noxious gas. No hydrogen gas is produced.
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
phosphoric acid H3PO4 sodium hydroxide NaOH H3PO4 + 3NaOH = Na3PO4 + 3H2O 1 acid + 3 base = 1 salt + 3 water
The balanced equation is: 2Al(s) + 3Zn(NO3)2(aq) -> 2Al(NO3)3(aq) + 3Zn(s)
the answer is 2 apex
Al(s) | Al3+(aq) Zn2+(aq) | Zn(s)
Zinc and Nitric acid react to produce Zinc nitrate, Water and Nitrogen Mono Oxide if the Nitric acid is Dilute... 3Zn + 8HNO3 = 3Zn[No3]2 + 4H20 + 2NO
When solid zinc reacts with aqueous gold(III) nitrate, zinc displaces gold in the compound through a single displacement reaction. The products of the reaction are gold metal and aqueous zinc nitrate.
In hot concentrated acid, nitric is an oxidizing acid: 3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O But in cold, dilute solutions: Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
2
Zinc (II) = Zn+2Hydroxide = OH-So Zinc Hydroxide = Zn(OH)2Hydrogen =H+ Phosphate = PO4-3So Hydrogen Phosphate = H3PO4So Zn(OH)2 + H3PO4 ---> Zn3(PO4)2 + H2O is the initial equation, but you need to balance it before you can do anything with it, that means that you need an equal amount of each element on each side of the equation.3 Zn(OH)2 + 2 H3PO4 ---> Zn3(PO4)2 + 6H2OIts easy to check the equation to make sure its balanced, just count your elements on each side of the arrow3Zn + 12H + 6O + 2PO4 on each side of the equation, and its balanced.
Write what you have first, Zn + FeCl3 ---> ZnCl2 + Fe Everything matches up except the Cl, we have 3 on the left and 2 on the right. To balance, we look for a common factor, which is 6. So we multiply the FeCl3 by 2 and the ZnCl2 by 3. Zn + 2FeCl3 ---> 3ZnCl2 + Fe Now we have 6 Cl on both sides but the Zn and Fe are unbalanced. Now we have 2 Fe on the left and 1 on the right. We have 1 Zn on the left and 3 on the right. So we multiply the reactant Zn by 3 and the product Fe by 2. 3Zn + 2FeCl3 ---> 3ZnCl2 + 2Fe Zn Zn Zn + ClFeCl ClFeCl ---> ClZnCl ClZnCl ClZnCl + Fe Fe Cl Cl 3 Zn, 6 Cl, 2 Fe ---> 6 Cl, 3 Zn, 2 Fe The same amount of each atom is on each side so it's balanced.
In this reaction, zinc displaces iron from iron chloride because it is higher in the reactivity series. The iron precipitate appears as a solid because it is no longer soluble in the solution. The balanced chemical equation for this reaction is: Zn + 2FeCl3 → 2Fe + 2ZnCl2.
Zn(NO3)2 + Na3PO4 yields Zn3(PO4)2 + NaNO3 with zinc phosphate being the precipitate.