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What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
When 15 g of NaClO3 and 20 g of Cr2O3 react which will limit the reaction?
To find the limiting reactant in a reaction, calculate the moles of each reactant present. Compare the moles of each reactant to the stoichiometry of the balanced chemical equation to see which reactant runs out first. Whichever reactant produces the least amount of product is the limiting reactant.
How many grams of iron can be made form 119 g of Fe2S3 and 12.7 g C?
To determine the amount of iron that can be produced from 119 g of Fe2S3 and 12.7 g of C, we first need to calculate the molar mass of Fe2S3 and C. The molar mass of Fe2S3 is approximately 207.9 g/mol, and the molar mass of C is approximately 12.01 g/mol. Next, we calculate the moles of Fe2S3 and C by dividing the given masses by their respective molar masses. Then, we determine the limiting reactant by comparing the moles of Fe2S3 and C. Finally, we use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of iron, which is approximately 42.4 grams.
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
Given The Equation 2 Al 3 Cl2 gives 2 AlCl3. What mass of product in grams can be produced from 4.40 g Al and 14.4 g Cl2?
To find the limiting reactant, first convert the masses of Al and Cl2 to moles. The balanced equation shows that 2 moles of Al reacts with 3 moles of Cl2 to produce 2 moles of AlCl3. Determine the moles produced by each reactant and find the limiting reactant. Finally, calculate the mass of AlCl3 produced using the limiting reactant.
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
If 108 grams of Al are allowed to completely react with 318 grams of FeO how many grams of AlO and Fe will be produced?
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
What is the maximum amount in grams of SO3 that can be produced by the reaction of 1.0g of S with 1.0g of O2 via the equation belowS O2-- SO3 not balanced?
To determine the maximum amount of SO3 that can be produced, we need to find the limiting reactant first. Given 1.0g of S and 1.0g of O2, we calculate the number of moles for each reactant. Then, we find the mole ratio from the unbalanced equation and determine which reactant is limiting. Finally, we can calculate the maximum amount of SO3 that can be produced from the limiting reactant.
Which is the limiting reactant when 3.00 moles of calcium are reacted with 8.00 moles of water in the following equation?
To determine the limiting reactant, you must compare the moles of each reactant to the stoichiometry of the reaction. The balanced equation is essential to determine the ratio of moles needed for the reaction. In this case, 3.00 moles of calcium and 8.00 moles of water are given, and you can find which reactant limits the reaction by finding out which reactant would require more moles for complete reaction based on the stoichiometry.
When 0.600 mol Mg3N2 reacts with 4.00 mol H2O what is the limiting reactant?
To find the limiting reactant, we first need to determine the amount of reactant in moles available for the reaction. Since one mole of Mg3N2 reacts with 6 moles of H2O, we calculate the moles of H2O available for the reaction. The limiting reactant is the one that produces the least amount of product given the stoichiometry of the reaction.
When 15 g of NaClO3 and 20 g of Cr2O3 react which will limit the reaction?
To find the limiting reactant in a reaction, calculate the moles of each reactant present. Compare the moles of each reactant to the stoichiometry of the balanced chemical equation to see which reactant runs out first. Whichever reactant produces the least amount of product is the limiting reactant.
How many grams of potassium cyanide PCl3 is produced from 93.0 grams of P4 (s) and 213 g of Cl2 (g) assuming the reaction goes to completion?
The balanced chemical equation for the reaction is: P4 (s) + 6Cl2 (g) -> 4PCl3 (s). To find the limiting reactant, we need to calculate the moles of P4 and Cl2 using their molar masses first. Then, we compare the amounts of PCl3 that can be produced from each reactant, and the smaller value (in moles) will be the limiting reactant. Finally, convert the moles of PCl3 to grams.
How many grams of silver nitrate can be produced by the reaction of 100.0 ml of 0.20 M silver nitrate and 100.0 ml of 0.15 M calcium chloride?
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
