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What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the number of manganese atoms that equal a mass of 54.94g?
To find the number of manganese atoms in 54.94 grams, you first need to know the molar mass of manganese, which is approximately 54.94 g/mol. This means that 54.94 grams of manganese corresponds to 1 mole of manganese atoms. Using Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mol, there are about (6.022 \times 10^{23}) manganese atoms in 54.94 grams.
When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
What is the molecular mass of manganese?
Manganese is a metal element. Atomic mass of it is 55.
What is of 25 m mol solution?
A 25 millimole (m mol) solution means there are 25 millimoles of solute in every liter of solution. It is a unit used to express the concentration of a solute in a solution.
How do you calculate the mass in grams of 2.5 mol Mn?
To calculate the mass in grams of 2.5 mol of manganese (Mn), you need to multiply the number of moles by the molar mass of manganese. The molar mass of manganese is approximately 54.94 g/mol. So, 2.5 mol of Mn would be 2.5 mol x 54.94 g/mol = 137.35 grams.
How do you make a 0.25 mol solution of sodium nitrite?
To make a 0.25 mol solution of sodium nitrite, measure out 8.25 grams of sodium nitrite (NaNO2) (sodium nitrite has a molar mass of 69.01 g/mol) and dissolve it in enough water to make a total volume of 1 liter. This will give you a 0.25 mol/L solution of sodium nitrite.
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the convsersion factor to convert MnO2 to Mn?
To convert manganese dioxide (MnO2) to manganese (Mn), you can use the molar mass of each compound. The molar mass of MnO2 is approximately 86.94 g/mol, while the molar mass of Mn is about 54.94 g/mol. Therefore, the conversion factor is 54.94 g of Mn per 86.94 g of MnO2, or approximately 0.6324. This means that for every gram of MnO2, you can obtain about 0.6324 grams of manganese.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution?
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
What is the number of manganese atoms that equal a mass of 54.94g?
To find the number of manganese atoms in 54.94 grams, you first need to know the molar mass of manganese, which is approximately 54.94 g/mol. This means that 54.94 grams of manganese corresponds to 1 mole of manganese atoms. Using Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mol, there are about (6.022 \times 10^{23}) manganese atoms in 54.94 grams.
What is the percentage of Mn in MnSo4?
Manganese sulfate (MnSO₄) consists of manganese (Mn), sulfur (S), and oxygen (O). The molecular weight of Mn is approximately 54.94 g/mol, sulfur is about 32.07 g/mol, and oxygen is around 16.00 g/mol (for four oxygen atoms, it's 64.00 g/mol). The total molecular weight of MnSO₄ is approximately 54.94 + 32.07 + 64.00 = 150.01 g/mol. Therefore, the percentage of manganese in MnSO₄ is (54.94 / 150.01) × 100, which is approximately 36.66%.
How would you make 100cm3 of 0 01 mol dm3 copper sulfate from a solution of 0 1 mol dm3 copper sulfate?
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
What is the concentration of the solution in mol/L?
The concentration of the solution is measured in moles per liter (mol/L).
How many sulfur dioxide molecules are there in 1.80 mol of sulfur dioxide?
There are 1.08 x 10^24 sulfur dioxide molecules in 1.80 mol of sulfur dioxide.
When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
How many grams of Na OH have been dissolved per liter of solution to make a 7.0 M Na OH solution?
To prepare a 7.0 M NaOH solution, you would add approximately 280 grams of NaOH per liter of water. This is because the molar mass of NaOH is 40 g/mol (Na = 23 g/mol, O = 16 g/mol, H = 1 g/mol), so to make a 7.0 M solution, you need 7 moles/liter x 40 g/mol = 280 g/L.
