100 KW divided by 415 volts is 241 amperes.
Power = voltage times current, so current = power divided by voltage.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the current (in amps) drawn by a 3-phase heater, you can use the formula: [ \text{Current (I)} = \frac{\text{Power (P)}}{\sqrt{3} \times \text{Voltage (V)}} ] For a 10.6 kW heater at 208 volts, the calculation would be: [ I = \frac{10,600 , \text{W}}{\sqrt{3} \times 208 , \text{V}} \approx 27.8 , \text{amps} ] Thus, the heater will draw approximately 27.8 amps.
To calculate the amperage, you can use the formula: Amps = (kW × 1000) / (√3 × Volts). Plugging in the values, we get: Amps = (45 × 1000) / (√3 × 208) ≈ 131.1 amps. So, the hot water heater would draw approximately 131.1 amps.
To answer this question the voltage of the heater must be given. I = W/E.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the amperage, you can use the formula: Amps = (kW × 1000) / (√3 × Volts). Plugging in the values, we get: Amps = (45 × 1000) / (√3 × 208) ≈ 131.1 amps. So, the hot water heater would draw approximately 131.1 amps.
The formula you are looking for is I = W/E.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
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For a 1hp 3-phase motor, the current draw will depend on the voltage supply. Typically, at 230V, a 1hp 3-phase motor will draw around 3.6 amps. However, this value may vary based on the motor efficiency and power factor.
To determine the amperage draw of a 5200 BTU heater, you can use the formula: Amps = BTUs / (Voltage x Efficiency). For example, if the heater operates at 120 volts and has an efficiency of about 100%, it would pull approximately 43.3 amps (5200 BTU / 120 volts). However, many small heaters operate at lower voltages (like 120V), so it's essential to check the specific heater's specifications for accurate amperage.
Assuming the power factor is 1, a 10 hp motor operating at 600 volts in a three-phase system would draw approximately 13.33 amps.