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Two(2).

They are ' Br^(2) ' . The terminal '2' indicates that there are two anions.

NB

Collectively they are IONS .

Positively charged ions are ' CATIONS'. M^(n+)

Negatively charged ions are ' ANIONS'. X^(n-)

MgBr2 =

Mg^(2+) ' positively charged cation

2Br^(-) ' negatively charged anions.

For an ionic compound to be neutral , the charged MUST balance and be opposite. (+/-)

Hence MgBr2 = 2+ for magnesium and "2 x -1 = -2 ' for the two bromines.

Hence + 2 - 2 = 0

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lenpollock

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∙ 2w ago

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