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Use this fomula: (m/M)*NA in which m is mass in gram (g), M is molar mass (g/mol) and NA is the Avogadro number (mol^-1)

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How many moles are in 3.6 x 10 to the 24 atoms of Cr?

To find the number of moles in 3.6 x 10^24 atoms of chromium, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). 3.6 x 10^24 atoms of Cr / 6.022 x 10^23 atoms/mol ≈ 5.98 moles of Cr.


Cr NH3 6 NO3 3 has how many elements and atoms?

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How many atoms are there in one molecule of Cr(NO3)3?

Chromium(III) nitrate is not made of molecules. It is ionic. There are 4 ions in one formula of chromium(III) nitrate.


How many Cr atoms are in 147.6 kg of chromium?

Quite a few! 147.6 kg chromium (1000 grams/1 kg)(1 mole Cr/52.00 grams)(6.022 X 1023/1 mole Cr) = 1.709 X 1027 atoms of chromium =========================


How many moles of Cr are there in a sample of Cr that contains 4.37E 23 atoms?

To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.


How many atoms are found in dichromate?

A dichromate ion (Cr2O7^2-) contains a total of 9 atoms - 2 chromium (Cr) atoms and 7 oxygen (O) atoms.


How many moles are present in 6.022 x 1023 atoms of Cr?

Only one mole of copper.


1.45gm of sample of chromium contains how much atoms?

To determine the number of atoms in 1.45g of chromium, you need to calculate the number of moles of chromium using its molar mass (51.996 g/mol) and then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. By dividing the mass of the sample by the molar mass, you can find the moles present, and then multiply the moles by Avogadro's number to find the number of atoms.


What is the oxidation number of Cr2O3?

+3 for Cr and -2 for O


How many Cr atoms are in 147.4 kg of chromium?

To find the number of chromium atoms in 147.4 kg of chromium, we first need to convert the mass to moles using the molar mass of chromium (51.996 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. The calculation would be (147.4 kg / 51.996 g/mol) * 6.022 x 10^23 atoms/mol.


How many chromium atoms and how many oxygen atoms are indicated on the right side of this balanced chemical equation 4 Crs 3 O2g 2 Cr2O3g?

In the balanced chemical equation 4 Cr(s) + 3 O2(g) → 2 Cr2O3(g), there are a total of 6 chromium atoms (2 from Cr and 4 from Cr2O3) and 6 oxygen atoms (6 from O2 and 3 from Cr2O3) on the right side of the equation.


How many atom in formula Na2CrO4?

The formula Na2CrO4 contains 7 atoms: 2 sodium atoms (Na), 1 chromium atom (Cr), and 4 oxygen atoms (O).