How many atoms are in 56.279 g of samarium?

Answer 1

56.279 grams Samarium(Sm) (1 mole Sm/150.36 grams)(6.022 X 10^23/1 mole Sm)

= 2.2540 X 10^23 atoms of Samarium

Answer 2

To determine the number of atoms in 56.279 g of samarium, you need to first calculate the number of moles using the molar mass of samarium (150.36 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.