0,2 mol sodium contain 1,204.10e23 atoms.
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
Washing soda, or sodium carbonate (Na2CO3), consists of sodium (Na), carbon (C), and oxygen (O). In 143 grams of washing soda, there are approximately 2 moles of Na2CO3 (since its molar mass is about 106 g/mol). This means there are 4 moles of sodium atoms (2 from each formula unit), 2 moles of carbon atoms, and 6 moles of oxygen atoms (3 from each formula unit). In terms of atoms, this corresponds to about 2.41 x 10²⁴ sodium atoms, 1.20 x 10²³ carbon atoms, and 3.61 x 10²⁴ oxygen atoms.
The answer is 0,111 moles.
molicules=3(6.02*10^23) =18.06*10^23 atoms=1*18.06*10^23 =18.06*10^23
I assume you mean 10.453x1023 atoms of sodium. 1 mole of anything contains 6.02x1023 representative particles (Avogadro's number), so if you divide the given number of atoms by Avogadro, you get 1.736 moles.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
1 mol has 6,022 140 857.10e23 atoms (The number of Avogadro).4 moles of sodium have 24,088 563 428.10e23 atoms.
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
There are approximately 1.81 x 10^24 atoms in 3.00 moles of sodium. This can be calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
1.56 X 10^21 atoms of sodium ( 1 mole Na/6.022 X 10^23) = 0.00259 moles sodium or 2.59 X 10^-3 moles sodium
Quite a few. 6.32 X 10^25 atoms sodium (1 mole Na/6.022 X 10^23) = 105 moles of sodium
To find the number of sodium atoms in 0.2310 g of sodium, you need to convert the mass to moles using the molar mass of sodium (22.99 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. This calculation will give you the number of sodium atoms present in 0.2310 g of sodium.
6.022 x 10^23 atoms of sodium is equal to 1 mole of sodium atoms according to Avogadro's number.
First calculate the moles of sodium moles = 500 g/ 23 = 21.739 ... Remember the Avogadro Number. 6.022 x 10^(23) is the number of atoms in one mole Hence , multiplying 6.022 x 10^(23) X 21.739... = 1.309 x 10^(25) atoms in 0.5 kg of sodium .