0
q = m x C x ΔT
q = amount of heat energy gained or lost in calories
m = mass of substance (in this case water) in grams = 10g
C = heat capacity of substance (in this case water) = 1cal/gram•oC
Tf = final temperature = 32 oC
Ti = initial temperature = 0 oC
ΔT = (Tf - Ti) = 32 oC
q = 10g x 1cal/gram•oC x 32 oC = 320 calories
What else can I help you with?
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.
How much energy is needed to melt 255.67 grams of ice?
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?
For water, the heat of fusion is 80 cal/g. So in other words, this is how many calories are needed to melt 1 gram of water that is frozen. Conversely, when you freeze 1 gram of water, you remove 80 calories of heat from it.... So, you multiply the calories needed to unfreeze a gram of water by the number of grams you have. In this case, 80 * 25 = 2000 Calories
How many calories is needed to heat 30g of water from 13C to 25C?
Using the formula Q=mcΔT, the amount of heat energy required is (30g)(4.18J g-1 K-1)(12K) = 1504.8J = 360 calories.
How much energy is needed to melt 5 grams of ice?
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How much heat is required to raise 2 grams of water 1 degree C?
The answer is 2 calories.
How many calories are required to melt a 1.52 g ice cube?
how many calories are required to melt a 1.52g ice cube?
How many calories would be needed to melt 10 grams of ice at 0 degrees C?
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
How much energy is needed to melt 255.67 grams of ice?
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
Difference between specific heat and calories?
Specific heat is the amount of heat required to raise the temperature of one gram of a substance by one degree Celsius, while calories are a unit of measurement for energy. Specific heat helps determine how much heat energy is needed to raise the temperature of a substance, while calories measure the amount of energy obtained from food or released during chemical reactions.
How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams for 0.0?
To calculate the energy required to heat water, you would need to know the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. Assuming we are heating the water by 1°C, the energy required would be 46.0g * 4.18J/g°C * 1°C = 192.28 Joules.
How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?
For water, the heat of fusion is 80 cal/g. So in other words, this is how many calories are needed to melt 1 gram of water that is frozen. Conversely, when you freeze 1 gram of water, you remove 80 calories of heat from it.... So, you multiply the calories needed to unfreeze a gram of water by the number of grams you have. In this case, 80 * 25 = 2000 Calories
How much energy is required to evaporate 5 grams toluene?
Toluene had heat of vaporization of 38.06 kJ/mol Toluene molecular mass is 92.14 g/mol You just need to convert heat of vaporization into kJ/g basis and multiply your 5 gram to get the required amount of heat.
A unit of heat that measures the energy available in foods?
calories.
The specific heat of gold is 0.031 caloriesgram and degC. If 10.0 grams of gold were heated and the temperature of the sample changed by 20.0 and degC how many calories of heat energy were absorbed by?
The needed heat is:Q = 10 x 20 x 0,031 = 6,2 calories
