they have 28 electrons and 14 electron shell.
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The sodium atom (Na) has 11 electrons. The electron configuration of sodium is 2-8-1. The third noble gas shell is the second energy level or shell, which can hold a maximum of 8 electrons. Therefore, the number of electrons in the third noble gas shell of sodium is 1.
Sodium (Na) has an atomic number of 11, which means it has 11 electrons. The electron configuration of sodium is 1s² 2s² 2p⁶ 3s¹. The inner shell electrons are those in the first and second energy levels, which include the 1s and 2s/2p electrons, totaling 10 inner shell electrons.
Sodium has one valence electron in its outermost shell (the third electron shell). To achieve a stable electron configuration, similar to that of the nearest noble gas (neon), sodium needs to lose this single valence electron rather than gain more. Therefore, sodium does not need additional valence electrons; it only needs to lose its one valence electron to achieve stability.
Sodium (Na) has an atomic number of 11, meaning it has 11 electrons. The electron configuration of sodium is 1s² 2s² 2p⁶ 3s¹. In the second shell, which includes the 2s and 2p subshells, there are 8 electrons (2 in the 2s and 6 in the 2p).
there is only one electron in the outermost shell of Na.
Sodium is in the third group in the periodic table. It meens that sodium has three shell. First shell - 2 electrons, second shell - 8 electrons, third shell (outer energy level) - 1 electron.
None - the electron goes from sodium TO the chlorine.
the valence shell is the outermost shell of an atom that has free electrons for taking part in chemical reactions... the valence shell of sodium has one free electron
In a sodium atom, there are 2 electrons in the innermost shell. The first shell can hold a maximum of 2 electrons. Sodium has an electron configuration of 2-8-1, so the inner shell contains 2 electrons.
Sodium has two electron shells: the first shell can hold up to 2 electrons, and the second shell can hold up to 8 electrons. Sodium has 11 electrons in total, with 2 in the first shell and 8 in the second shell.
The first electron shell of any element is the one s shell. Every element except hydrogen has 2 one s electrons.
One chlorine atom has 7 electrons in its outer shell, and sodium has 1 electron in its outer shell. Therefore, sodium can donate its electron to chlorine, forming a stable compound where chlorine has a full outer shell with 8 electrons.
A sodium atom has 1 electron in its valence shell, while a chlorine atom has 7 electrons in its valence shell. When sodium reacts with chlorine to form sodium chloride, the sodium atom loses its 1 electron to achieve a stable octet configuration, while the chlorine atom gains this electron. The resulting sodium chloride molecule has 8 electrons in the valence shell of the chlorine atom.
Sodium has 1 electron in its outer shell, and it needs to lose that one electron to achieve a full outer shell (valence shell) with 8 electrons. By losing this one electron, sodium will achieve a stable electron configuration similar to that of the noble gas neon.
Sodium has 1 electron in its outer shell, while chlorine has 7 electrons in its outer shell. To achieve a stable electron configuration, sodium will donate its electron to chlorine, forming an ionic bond. This results in sodium losing 1 electron and chlorine gaining 1 electron to form sodium chloride.
1 Its electron configuration is 1s22s22p63s1. A good periodic table that includes electron configurations can be found under related links.
Sodium would need to gain 7 electrons to fill its valance shell. Instead of doing that, however, sodium will lose the one valence electron it does have, leaving behind the shell below it, which is already full.