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How do you calculate the number of moles of bromine present in 16.0ml of Br2 whose density is 3.12gml?

First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.


What is the mass (in kg) of 3.2 L of Br2?

The molar mass of Br2 is 159.808 g/mol. To convert 3.2 L to grams, you need to use the density of Br2, which is approximately 3.12 g/mL. Then convert grams to kilograms to get the mass in kg, which would be around 10 kg.


What is the mass of 4.89 x 1020 molecules of Br2?

To calculate the mass of 4.89 x 10^20 molecules of Br2, you need to use the molar mass of Br2, which is 159.808 g/mol. Calculate the number of moles of Br2: 4.89 x 10^20 molecules / 6.022 x 10^23 molecules/mol = 8.13 x 10^-4 moles Use the formula mass = moles x molar mass to find the mass: mass = 8.13 x 10^-4 moles x 159.808 g/mol ≈ 0.130 g


How many moles are contained in 44.0 g Br2?

To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.


Given the density of Br2 What is the molecular weight?

The molecular weight of a compound is the sum of the atomic weights of all the atoms in a molecule. For bromine (Br2), the density doesn't directly provide information about the molecular weight. The molecular weight of bromine (Br2) is approximately 159.808 g/mol.


How many atoms are in 1.54 moles of Bromine?

1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2


How many grams of co2 are in 2l mol of the compound?

92.4 grams


How many grams in 4.23 m mol of HBr?

The answer is 0,3422 grams.


How many grams are present in 0.20 mol of Na?

To determine the number of grams present in 0.20 mol of Na, you need to use the molar mass of sodium, which is approximately 23 grams/mol. Therefore, 0.20 mol of Na is equal to 0.20 mol x 23 g/mol = 4.6 grams of Na.


Are the number of atoms of bromine in 1 mol Br2 equal to avogadro's number?

No, the number of atoms in 1 mol of Br2 is equal to Avogadro's number multiplied by 2, because there are 2 atoms of bromine in each molecule of Br2. Avogadro's number represents the number of entities (atoms, molecules, etc.) in 1 mol of a substance.


2 cl plus br2 chemical reaction?

The chemical reaction between 2 mol of Cl2 and Br2 forms 2 mol of ClBr3, a molecule known as chlorine bromide. The balanced chemical equation for this reaction is: 2 Cl2 + Br2 → 2 ClBr3.


How many grams of ccl4 are needed to have 5.000 mol?

To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.