0
What else can I help you with?
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of oxygen atoms are in 4.25 moles of calcium carbonate the chief constituent of seashells?
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
How many grams of calcium carbonate are needed to produce 71.0 L of carbon dioxide at STP?
Assuming complete reaction, the molar volume of gas at STP is 22.4 L. Therefore, 71.0 L of CO2 corresponds to 71.0/22.4 = 3.17 moles of CO2. From the balanced chemical equation for the reaction of calcium carbonate (CaCO3) -> CaO + CO2, 1 mole of CaCO3 produces 1 mole of CO2. So, 3.17 moles of CO2 requires 3.17 moles of CaCO3. The molar mass of CaCO3 is 100.1 g/mol, so 3.17 moles of CaCO3 would be 3.17 * 100.1 = 317.6 grams of CaCO3.
What is the mass of 0.5 moles of calcium carbonate (CaCO3)?
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
How many moles of carbon are in 3.5 moles of calcium carbonate?
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
How many Ca atoms are found in 0.50 moles of CaCO3?
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
How many moles of calcium atoms are 2.5 moles of calcium carbonate CaCO3?
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of oxygen atoms are in 4.25 moles of calcium carbonate the chief constituent of seashells?
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
How many moles of oxygen are in one mole of calcium carbonate?
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
When calcium carbonate decomposes according to the equation caco3-cao CO2 how many grams of CO2 are produced from the decomposition of 520 g of caco3?
To find the grams of CO2 produced from the decomposition of 520 g of CaCO3, we first need to calculate the molar mass of CaCO3, which is 100.09 g/mol. This means 520 g of CaCO3 is equal to 5.19 moles. From the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CO2. Therefore, 5.19 moles of CaCO3 will produce 5.19 moles of CO2 which is equal to 235.10 g of CO2.
How many grams of calcium carbonate are needed to produce 71.0 L of carbon dioxide at STP?
Assuming complete reaction, the molar volume of gas at STP is 22.4 L. Therefore, 71.0 L of CO2 corresponds to 71.0/22.4 = 3.17 moles of CO2. From the balanced chemical equation for the reaction of calcium carbonate (CaCO3) -> CaO + CO2, 1 mole of CaCO3 produces 1 mole of CO2. So, 3.17 moles of CO2 requires 3.17 moles of CaCO3. The molar mass of CaCO3 is 100.1 g/mol, so 3.17 moles of CaCO3 would be 3.17 * 100.1 = 317.6 grams of CaCO3.
What is the mass of 0.5 moles of calcium carbonate (CaCO3)?
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
How many moles of calcium carbonate are in 1.719 grams?
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
How many o atoms are present in 50gram of caco3?
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
